Answer:
A single compound is simultaneously oxidized and reduced.
Explanation:
In chemistry, disproportionation is a simultaneous oxidation and reduction of a single chemical specie.
What this means is that; in a disproportionation reaction, only one compound is both oxidized and reduced. This implies that two products are formed during disproportionation. One is the oxidized product while the other is the reduced product.
Consider the disproportionation of CuCl shown below;
2CuCl -----> CuCl2 + Cu
Here, CuCl2 is the oxidized product while Cu is the reduced product.
Answer:
50 g NaOH
General Formulas and Concepts:
<u>Chemistry - Solutions</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Molarity = moles of solute / liters of solution
Explanation:
<u>Step 1: Define</u>
0.500 L
2.50 M NaOH
x moles of solute
<u>Step 2: Define conversions</u>
Molar Mass of Na - 22.99 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of NaOH - 22.99 + 16.00 + 1.01 = 40 g/mol
<u>Step 3: Find moles of solute</u>
2.50 M NaOH = x moles NaOH / 0.500 L
x = 1.25 moles NaOH
<u>Step 4: Convert</u>
<u /> = 50 g NaOH
<u>Step 5: Check</u>
<em>We are given 3 sig figs. Since our final answer has 2 sigs, there is no need to round.</em>
Answer:
It forms an octahedral complex
Rh[NH3]5I
Explanation:
Or see structure attached below