Can you give a picture description? Or any answer choices?
Answer:
Physical properties
Explanation:
These properties are the ones that you can observe or collect by your senses, for example the color, the odor, the sound, the texture, etc. In this case the substance is not going to change to a new one, it could be that is changing of state.
Answer:
Oxidized : CO
Reduced: Fe
Oxidizing agent: Fe2O3
Reducing agent: CO
Explanation:
Loss of electrons is oxidation while gaining of electrons is reduction.
CO is a reducing agent, Fe2O3 is an oxidizing agent.
Each carbon atom is oxidized in CO. CO is the reducing agent
Each Fe atom in FeO3 is reduced. FeO3 is the oxidizing agent
You are given both the energy level, n = 4, and the subshell, l = 3 on which the electrons reside.
The subshell is given to you by the angular momentum quantum number, l which can take value that ranges from 0 to n − 1
l = 0 → the s-subshell
l = 1 → the p-subshell
l = 2 → the d-subshell
l = 3 → the f-subshell
<u>For n = 4 and l = 3, ml can be -3, -2, -1, 0, +2, +2, and +3. </u>
<u>Each of these can have 2 electrons (+1/2 and -1/2 spin) for a total of 14 electrons.</u>
Answer:
B. They are stereoisomers
C. They are enantiomers
Explanation:
Let us consider all the options
A. D and L-glucose are not necessarily furanose, they can also be in free form (open chain) or as a six-membered ring (pyranose)
B. These sugars are stereoisomers as they have the same molecular formula, same bonds but with the different spacial arrangement.
C. Two structures are called enantiomers, if they are stereoisomers and are mirror images of each other and are not-superimposable. The given pair of structures satisfy these conditions
D. Epimers are diastereoisomers (same molecular formula and connectivity having a different spacial arrangement but are not mirror images and non-superimposable) with only one different stereocenter (if there are more than one). This is not the case
E. All monosaccharides (any sugar that cannot be hydrolysed to a simpler sugar) are reducing sugars. So, this option is invalid
