The actual yield is 43 g Cl₂.
The <em>limiting reactant was MnO₂</em> because it gave the smaller mass of Cl₂.
∴ The <em>theoretical yield</em> is 60.25 g Cl₂.
% yield = actual yield/theoretical yield × 100 %
Actual yield = theoretical yield × (% yield/100 %) = 60.25 g × (72 %/100%) = 43 g
Answer:
8700
Explanation:
First, do the operations i<em>nside parentheses</em>.
102 900/12 = 8600 2 sfs because of 12
170/1.27 = 130 2 sfs because of trailing 0 in 170
===============
Now, do the addition.
8600
<u> + </u><u>13</u><u>0
</u>
8700
The answer has two significant figures because when adding, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.
The last significant figure in 8600 (the 6, in the hundreds place) is further to the left than the last significant figure in 130 (the 3, in the tens place).
We round off to the nearest hundred and get the answer, 8700.
Hey, for #1, it's 1, 1, 1 because it's already balanced!
For #2, it's 1, 2, 1, 1 since the product side has 2 Cl's but left side only had 1.
Answer:
Molar mass = [9(12.0)+8(1.01)+4(16.0)] = 180.1 g/mol Moles = 112 g 1 mol x 180.1 g = 0.622 mol (3 sig figs)
Explanation:
