Answer:
Fisheries science. This discipline aims to study and understand fisheries biology, food web, the predator-prey relationship, stock status information, as well as the socioeconomic status of fishermen (commercial and substantial)
Explanation:
The information from this discipline will help environmental scientists understand why there is a decrease in fish in the ocean. The reasons can vary from over fishing to decline in the reproduction of fishes due to climate change.
Find the moles of CaO
divide mass (2.0g) by the RFM which is 56 (Ca is 40 add that to O which is 16 making 56) this gives 0.0356 moles.
Find the theoretical mass by multiplying the moles of CaO (which is 0.0356 as there are no balancing number making the ratio 1:1) by the RFM of Ca(OH)2 which is 74 (40+16+16+1+1)
74 (Ca(OH)2 RFM) x 0.0357 (CaO moles) = 2.6g which is the theoretical mass of Ca(OH)2
Find percentage yield by dividing the actual mass of Ca(OH)2 by the theoretical and then x100 this Should give you 82.3%
Answer:
A. 96.3 mg/dL
Absolute error: 5.7 mg/dL
Relative error: 5.6%
B. 97.2 mg/dL
Absolute error: 4.8 mg/dL
Relative error: 4.7%
C. 104.8 mg/dL
Absolute error: 2.8 mg/dL
Relative error: 2.7%
D. 111.5 mg/dL
Absolute error: 9.5 mg/dL
Relative error: 9.3%
E. 110.5 mg/dL
Absolute error: 8.5 mg/dL
Relative error: 8.3%
Explanation:
The formula for the absolute error is:
Absolute error = |Actual Value - Measured Value|
The formula for the relative error is:
Relative error = |Absolute error/Actual value|
In your exercise, we have that
Actual Value = 102.0 mg/dL
A. 96.3 mg/dL:
![E_{ABS} = |102.0 - 96.3| = 5.7mg/dL](https://tex.z-dn.net/?f=E_%7BABS%7D%20%3D%20%7C102.0%20-%2096.3%7C%20%3D%205.7mg%2FdL)
![E_{R} = \frac{5.7}{102} = 0.056 = 5.6%](https://tex.z-dn.net/?f=E_%7BR%7D%20%3D%20%5Cfrac%7B5.7%7D%7B102%7D%20%3D%200.056%20%3D%205.6%25)
B. 97.2 mg/dL
![E_{ABS} = |102.0 - 97.2| = 4.8mg/dL](https://tex.z-dn.net/?f=E_%7BABS%7D%20%3D%20%7C102.0%20-%2097.2%7C%20%3D%204.8mg%2FdL)
![E_{R} = \frac{4.8}{102} = 0.047 = 4.7%](https://tex.z-dn.net/?f=E_%7BR%7D%20%3D%20%5Cfrac%7B4.8%7D%7B102%7D%20%3D%200.047%20%3D%204.7%25)
C. 104.8 mg/dL
![E_{ABS} = |102.0 - 104.8| = 2.8mg/dL](https://tex.z-dn.net/?f=E_%7BABS%7D%20%3D%20%7C102.0%20-%20104.8%7C%20%3D%202.8mg%2FdL)
![E_{R} = \frac{2.8}{102} = 0.027 = 2.7%](https://tex.z-dn.net/?f=E_%7BR%7D%20%3D%20%5Cfrac%7B2.8%7D%7B102%7D%20%3D%200.027%20%3D%202.7%25)
D. 111.5 mg/dL
![E_{ABS} = |102.0 - 111.5| = 9.5mg/dL](https://tex.z-dn.net/?f=E_%7BABS%7D%20%3D%20%7C102.0%20-%20111.5%7C%20%3D%209.5mg%2FdL)
![E_{R} = \frac{9.5}{102} = 0.093 = 9.3%](https://tex.z-dn.net/?f=E_%7BR%7D%20%3D%20%5Cfrac%7B9.5%7D%7B102%7D%20%3D%200.093%20%3D%209.3%25)
E. 110.5 mg/dL
![E_{ABS} = |102.0 - 111.5| = 8.5mg/dL](https://tex.z-dn.net/?f=E_%7BABS%7D%20%3D%20%7C102.0%20-%20111.5%7C%20%3D%208.5mg%2FdL)
![E_{R} = \frac{8.5}{102} = 0.083 = 8.3%](https://tex.z-dn.net/?f=E_%7BR%7D%20%3D%20%5Cfrac%7B8.5%7D%7B102%7D%20%3D%200.083%20%3D%208.3%25)
Answer:
162.7miles/hr
Explanation:
Given parameters:
Distance covered by the train = 813.5miles
Time taken = 5hours
Unknown:
Speed of the train = ?
Solution:
Speed is a physical quantity.
It is mathematically expressed as;
Speed =
So, input parameters and solve;
Speed =
= 162.7miles/hr
Covalent bond forms between the oxygen and hydrogen atoms.
(I attached a picture that could help)
-Hope that helps,
Good luck!