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Ierofanga [76]
2 years ago
13

What type of wave carry sound energy forward?

Physics
1 answer:
VladimirAG [237]2 years ago
3 0
Longitudinal waves or better known as pressure waves
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A woman at an airport is towing her 20.0-kg suitcase at constant speed by pulling on a strap at an angle θ above the horizontal.
Elza [17]

Answer:

Normal force: 167.48 N

Explanation:

  • First of all it is necessary to draw the free body diagram of the suitcase adding alll the forces stated on the question: the normal force, the friction force and pull force exterted by the woman. Additionally, we need to add the weight, the forces exerted by Earth's gravity. I attached the diagram so you can check it.
  • We need to resolve all the unknown quantities on this exercise, so we need to write down the sum of forces equations on X-Axis and Y-axis. Remember that force exerted by the woman has an angle with respect the horizontal (X-Axis),  that is to say it has force compoents on both X and Y axis.  The equations  will be equal to zero since the suitcase  is at constant speed (acceleration is zero).

        ∑F_{x}:  F{x}-20 = 0  

        ∑F_{y}: N -W+F_{y}=0

  • Our objetive is to find the value of the normal force. It means we can solve the sum of Y-axis for N. The solution would be following:

       N = W - Fy

  • Keep in mind Weight of the suitcase (W) is equal to the suitcase mass times the acceleration caused by gravity (9.81\frac{m}{s^{2}}. Furthermore, Fy can be replaced using trigonometry as Fsin(\theta) where θ is the angle above the horizontal. So the formula can be written in this way:

        N = mg -Fsin(\theta)

  • We need to find the value of θ so we can find the value of N. We can find it out solving the sum of forces on X-axis replacing <em>Fx</em> for Fcos(θ). The equation will be like this:

        Fcos(\theta) -20 = 0   ⇒   Fcos(\theta) = 20\theta                            [tex]\theta=cos^{-1}(20/F)

  • Replacing the value of F we will see θ has a value of 55.15°. Now we can use this angle to find the value of N. Replacing mass, the gravity acceleration and the angle by their respective values, we will have the following:

       N = 20 x 9.81 - 35sin(55.15)  ⇒ N = 167.48 N

7 0
3 years ago
A bullet is fired in a horizontal direction with a muzzle velocity of 300m/s.In the absence of air resistance,how far will it ha
Kruka [31]

Answer:

304.9m

Explanation:

Given

Velocity = 300m/s

Tim = 1sec

Required

Horizontal distance S

Using the formula

S= ut+1/2gt²

S = 300(1)+1/2(9.8)(1)²

S = 300+4.9

S = 304.9m

Hence the distance travelled is 304.9m

6 0
2 years ago
Who might be experiencing psychosis?
aleksandrvk [35]

Answer:

D

Explanation:

I think the answer is D, because of hallucinations

4 0
3 years ago
A worker pushes horizontally on a large crate with a force of 265.0 N and the crate moved 4.3 m. How much work was done?
trapecia [35]

Answer:

<h2>1139.5 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

work done = 265 × 4.3 = 1139.5

We have the final answer as

<h3>1139.5 J</h3>

Hope this helps you

8 0
2 years ago
A 2.03 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.602 and t
diamong [38]

Answer:

11.98 N

Explanation:

Normal force =   mg =  2.03 * 9.81

coeff of static friction must be overcome for the book to begin moving

       .602 = F / (2.03 * 9.81)   = 11.98  N

5 0
2 years ago
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