Answer:
Given: Vi = 382 km/h, Vf = 0 km/h, Mc = 705 kg, Md = 65 kg, Δt = 12
Required: Δx
F = Δp / Δt
= ![\frac{(Mc+Md)Vf-(Mc+Md)Vi}{t} \\\\= 6.81 * 10x^{3} N [left]\\\\x=\frac{1}{2} (Vi+Vf)\\ \\ = 637m[right]](https://tex.z-dn.net/?f=%5Cfrac%7B%28Mc%2BMd%29Vf-%28Mc%2BMd%29Vi%7D%7Bt%7D%20%5C%5C%5C%5C%3D%206.81%20%2A%2010x%5E%7B3%7D%20N%20%5Bleft%5D%5C%5C%5C%5Cx%3D%5Cfrac%7B1%7D%7B2%7D%20%28Vi%2BVf%29%5C%5C%20%5C%5C%20%3D%20637m%5Bright%5D)
Any mental health disorders- mental health is a huge discussion right now, and it’s mental health awareness month! perfect timing for your project :-)
Answer:
2.1 s
Explanation:
The motion of the ball is a projectile motion. We know that the horizontal range of the ball is

And that the initial speed of the ball is

at an angle of

So, the horizontal speed of the ball (which is constant during the entire motion) is

And since the horizontal range is 50 m, the time taken for the ball to cover this distance was

which is the time the ball spent in air.
EXPLAIN MORE!!! i need more detail if i can help you