Question

A quarterback throws a pass at an angle of 35◦ above the horizontal with an initial speed of 25 m/s. the receiver catches the ball 2.55 s later. determine the distance the ball was thrown.

Answer 1

As this is the projectile motion means the motion of object under constant acceleration, so we use all eq. of motion under constant acceleration.

Angle above horizontal=θ= 35°
Initial speed= v₁ = 25 m/s
Time of flight= t= 2.55 s
Now,
from eq. of motion
x=x₁ + (v₁*cosθ)(t)+1/2 *a*t²
As, there is no acceleration in horizontal direction so a=0 and also initial displacement x₁=0
x= 25*cos(35)*2.55
x=52.22 m