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devlian [24]
3 years ago
11

The blank is the the distance between two crests or two troughs on a transverse wave. It is also the distance between compressio

ns or the distance between rarefactions on a longitudinal wave.
Physics
2 answers:
den301095 [7]3 years ago
6 0
"Wavelength" is the distance between two crests or two Troughs.

It is the <span>distance between compressions or the distance between rarefactions on a longitudinal wave too!

So, your final answer is "Wavelength".

Hope this helps!!</span>
dlinn [17]3 years ago
3 0

Answer : Wavelength.

Explanation :

A disturbance created in a medium produces wave.

In transverse wave, the particles of the medium moves in the direction perpendicular to the direction of propagation of wave.

The uppermost portion of the wave is called the crest and the lower most portion is called the trough.

In longitudinal wave, the particles of medium moves in the same direction of wave i.e. in the direction parallel to the wave.

The particles of medium in longitudinal wave forms compressions and rarefactions. In compression the density of particles in more in a particular space while in rarefaction it is less.

Hence, the wavelength is the the distance between two crests or two troughs on a transverse wave.

It is also the distance between compressions or the distance between rarefactions on a longitudinal wave.

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Calculate the induced electric field (in V/m) in a 40-turn coil with a diameter of 11 cm that is placed in a spatially uniform m
Naddik [55]

Answer:

Explanation:

Given that,

Number of turn N = 40

Diameter of the coil d= 11cm = 0.11m

Then, radius = d/2 = 0.11/2 =0.055m

r = 0.055m

Then, the area is given as

A =πr²

A = π × 0.055²

A = 9.503 × 10^-3 m²

Magnetic Field B = 0.35T

Magnetic field reduce to zero in 0.1s, t = 0.1s

so we want to find induce electric field. To find the electric field,(E) we need to find the electric potential (V).

E.M.F is given as

ε = —N • dΦ/dt

Where magnetic flux is given as

Φ = BA

Then, ε = —N • dΦ/dt

ε = —N • dBA/dt

ε = —NBA/t

Then, its magnitude is

ε = NBA/t

Inserting the values of N, B, A and t

ε = 40×0.35×9.503×10^-3/0.1

ε = 1.33 V

Then, using the relationship between Electric field and electric potential

V = Ed

ε = E•d

E = ε/d

E = 1.33/0.11

E = 12.09 V/m

7 0
3 years ago
A 25.0-kg child is standing at the edge of a horizontal merry-go-round with a radius of 2.40 m and a moment of inertia of 356 kg
motikmotik

Answer:

\omega_{f}=1.634\ rad/s  

Explanation:

given,  

diameter of merry - go - round = 2.40 m  

moment of inertia = I = 356 kg∙m²

speed of the merry- go-round = 1.80 rad/s

mass of child = 25 kg  

initial angular momentum of the system  

L_i = I\omega_i  

L_i =356\times 1.80  

L_i =640.8\ kg.m^2/s  

final angular momentum of the system  

L_f = (I_{disk}+mR^2)\omega_{f}  

L_f = (356 + 25\times 1.2^2)\omega_{f}  

L_f= (392)\omega_{f}  

from conservation of angular momentum  

L_i = L_f  

640.8= (392)\omega_{f}  

\omega_{f}=1.634\ rad/s  

8 0
3 years ago
Read 2 more answers
In a double-slit experiment, the slits are illuminated by a monochromatic, coherent light source having a wavelength of 609 nm.
Ray Of Light [21]

Answer:

\Delta x = 3.65 \mu m

Explanation:

As we know that the sixth order maximum will have path difference given as

\Delta x = N\lambda

here we know that

N = order of maximum

\lambda = 609 nm

now we have

N = 6

so we know that

\Delta x = 6(609 nm)

\Delta x = 3.65 \mu m

6 0
3 years ago
The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the magnitude of the
PIT_PIT [208]

The drag force is directly proportional to the square of the velocity of motion of the object. So as the speed is doubled, the magnitude of drag force will get quadrupled.

<u>Explanation: </u>

Drag force is the opposing or resisting force acting on any object by the medium in which it is moving. So in this case, you are riding a bicycle, thus the medium can be considered as air.

The formula for calculating drag force is as below:

               \text {Drag force }=\frac{1}{2} \rho v^{2} C_{D} A

Here, ρ is the density of the air molecules, v is the velocity or speed of the bicycle, CD is the drag coefficient and A is the area of the bicycle.

In the above equation, only the term velocity will be a varying quantity with respect to time and other quantities will remain constant throughout the single situation of riding of bicycle.

So, the equation can be,

             \text { Drag force }=k v^{2}

Where ,  

     k=\frac{1}{2} \rho C_{D} A (constant for this whole condition)

Now given the speed of bicycle increased from v to 2v, so the initial drag force will be

                   N_{i}=k v^{2}

After increase in speed, the final drag force will be  

                   N_{f}=k(2 v)^{2}

                   N_{f}=4 k v^{2}=4 N_{i}

Thus, if the speed of the bicycle is doubled, the drag force will get increased by four times.

4 0
3 years ago
Determine the total momentum before the impact. Picture attached.
ipn [44]

Answer:

Explanation:

C

8 0
3 years ago
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