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Galina-37 [17]
3 years ago
14

A small private college is interested in determining the percentage of its students who live off campus and drive to class. Spec

ifically, it was desired to determine if less than 20% of their current students live off campus and drive to class. Find the large-sample rejection region for the test of interest to the college when using a level of significance of 0.01.
Mathematics
1 answer:
Naily [24]3 years ago
6 0

Answer:

The rejection region is the one defined by z<-2.326.

Step-by-step explanation:

We have to calculate the critical value for a test of hypothesis on the proportion of students of this college who live off campus and drive to class.

The sample is large enough, so we can use the z-statistic.

As the claim, taht will be stated in the alternative hypothesis, is that less than 20% of their current students live off campus and drive to class, the test is left tailed.

Alternative hypothesis:

Ha: \pi

Then, for a significance level of 0.01, 99% of the data has to be over (or 1% below) this critical z-value.

In the standard normal distribution this z-value is z=-2.326.

P(z

The critical value that divide the regions is z=-2.326. The rejection region is the one defined by z<-2.326.

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For this case we have to by definition, if two lines are perpendicular then the product of its slopes is -1.

That is to say:

m_ {1} * m_ {2} = - 1

We have the following equation:

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So:

m_ {1} = - 2

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Option A:

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Option D:

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The correct option is option B

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3 years ago
Karen, Janet, Brian, and José ran for class president, Jose received 32% of the vote and Janet received 21%. What percentages co
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