Answer:
Explanation:
2 NO2(g) ⇄ N2O4(g)
Adding Argon to this reaction will have NO effect. Catalysts nor inert gases have an affect on equilibrium conditions.
Only changes in concentration, temperature conditions and pressure-volume conditions (unless both sides have equal molar volumes) will affect the equilibria.
NH4OH(aq) ⇄ NH3(g) + H2O(l)
Removing ammonia from reaction equilibrium causes the reaction to shift right to replace removed ammonia. => Think of the reaction as being on a seesaw => removing ammonia from the product side tilts the seesaw left causing the NH₄OH to decompose and deliver more NH₃ and H₂O to the product side to increase weight on that side and level the seesaw. :-)
Answer:
it have 10 neutrons and it is Fluorine(F).
As per Le Chatelier principle, when a system in equilibrium is disturbed, the reaction will try to compensate the change to restore the equilibrium.
This reaction occurs in gas phase, so the volume is inversely proportional to the pressure.
Then a decrease in volume will cause an increase in pressure, so the system will tend to react in the direction that compensates this increase, this is the system will try to reduce the number of moles of particles to reduce the increase of the pressure.
As you see, there are 3 particles of products (2 of NO and 1 of Br) for every 2 particles of reactant (NOBr).
That means, that the equilibrium will displace to the left, this is the concentration of NOBr will increase while the concentration of NO and Br will decrease.
Answer:
+4
Explanation:
The oxidation number of C in carbon dioxide (CO2) is (rules 1 & 2): 0 + (2 x 2) = +4 [Check (rule 3): +4 + 2(-2) = 0] The oxidation number of C in methane (CH4) is (rules 1 & 2): 0 – (4 x1) = -4 [Check (rule 3): -4 + 4(-1) = 0].
