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jonny [76]
3 years ago
10

If the density of water is 1.00 g/mL and the density of mercury is 13.6 g/mL, how high a column of water in meters can be suppor

ted by standard atmospheric pressure?
Chemistry
1 answer:
dexar [7]3 years ago
4 0

Answer:

The answer to this is

The column of water in meters that can be supported by standard atmospheric pressure is 10.336 meters

Explanation:

To solve this we first list out the variables thus

Density of the water = 1.00 g/mL =1000 kg/m³

density of mercury  = 13.6 g/mL = 13600 kg/m³

Standard atmospheric pressure = 760 mmHg or 101.325 kilopascals

Therefore from the equation for denstity we have

Density = mass/volume

Pressure = Force/Area  and for  a column of water, pressure = Density × gravity×height

Therefore where standard atmospheric pressure = 760 mmHg we have for Standard tmospheric pressure= 13600 kg/m³ × 9.81 m/s² × 0.76 m = 101396.16 Pa

This value of pressure should be supported by the column of water as follows

Pressure = 101396.16 Pa =  kg/m³×9.81 m/s² ×h

∴  h = \frac{101396.16}{(1000)(9.81)} = 10.336 meters

The column of water in meters that can be supported by standard atmospheric pressure is 10.336 meters

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The enthalpy change of the reaction below (ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

The bond energies data is given as follows:

BE  for C≡O  = 1072 kJ/mol

BE for Cl-Cl = 242 kJ/mol

BE for C-Cl = 328 kJ/mol

BE for C=O = 766 kJ/mol

The enthalpy change for the reaction is given as :

ΔHr×n = ∑H reactant bond - ∑H product bond

ΔHr×n = ( BE C≡O + BE Cl-Cl) - ( BE C=O + BE 2 × Cl-Cl )

ΔHr×n = ( 1072 + 242 ) - ( 766 + 656 )

ΔHr×n = 1314 - 1422

ΔHr×n = - 108 kJ

Thus, The enthalpy change of the reaction below ( ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

To learn more about enthalpy here

brainly.com/question/13981382

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Identify the heterogeneous mixtures from the list. Check all that apply. salad dressing hydrochloric acid solution orange juice
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Answer:

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Explanation:

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What are the period and group trends in electronegativities
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Electronegativity of an element decreases as we move down a group on the periodic table and electronegativity increases while moving from left to right across a period on the periodic table.

Explanation:

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If an isotope of an element has 40 neutrons and a mass number of 79, how many electrons must it have?
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As you have seen, ozone is formed in the upper atmosphere through the reaction:
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The rate law equation for Ozone reaction

r=k[O][O₂]

<h3>Further explanation</h3>

Given

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For reaction

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The rate law can be formulated:

\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}

where

r = reaction rate, M / s

k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹

a = reaction order to A

b = reaction order to B

[A] = [B] = concentration of substances

So for Ozone reaction, the rate law (first orde for both O and O₂) :

\tt \boxed{\bold{r=k[O][O_2]}}

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