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kenny6666 [7]
3 years ago
15

An Object is moving due south at 16 m/s, when a force accelerates it at 4m/s in a southerly direction. How long will it take for

the object to reach a velocity of 48 m/s south. Please help me out.
Physics
1 answer:
N76 [4]3 years ago
6 0

Answer:

Time taken to accelerate to 48 m/s =  8 seconds

Explanation:

Initially the object is moving south at = 16 m/s

So, initial velocity of the object = 16 m/s

Acceleration caused by the force = 4 m/s^2

Final velocity towards south = 48 m/s

Using equation of motions:

v_f=v_i+at

where

v_f\rightarrow final velocity

v_i\rightarrow initial velocity

a\rightarrow acceleration

t\rightarrow time

Plugging in values.

48=16+(4)t

48=16+4t

Subtracting both sides by 16

48-16=16+4t-16

32=4t

Dividing both side by 4.

\frac{32}{4}=\frac{4t}{4}

8=t

∴ t=8

Time taken to accelerate to 48 m/s =  8 seconds

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The electric field of a sinusoidal electromagnetic wave obeys the equation E = (375V /m) cos[(1.99× 107rad/m)x + (5.97 × 1015rad
kenny6666 [7]

Answer:

a)  v = 2,9992 10⁸ m / s , b)  Eo = 375 V / m ,  B = 1.25 10⁻⁶ T,

c)     λ = 3,157 10⁻⁷ m,   f = 9.50 10¹⁴ Hz ,  T = 1.05 10⁻¹⁵ s , UV

Explanation:

In this problem they give us the equation of the traveling wave

        E = 375 cos [1.99 10⁷ x + 5.97 10¹⁵ t]

a) what the wave velocity

all waves must meet

        v = λ f

In this case, because of an electromagnetic wave, the speed must be the speed of light.

        k = 2π / λ

        λ = 2π / k

        λ = 2π / 1.99 10⁷

        λ = 3,157 10⁻⁷ m

        w = 2π f

        f = w / 2 π

        f = 5.97 10¹⁵ / 2π

        f = 9.50 10¹⁴ Hz

the wave speed is

        v = 3,157 10⁻⁷   9.50 10¹⁴

        v = 2,9992 10⁸ m / s

b) The electric field is

           Eo = 375 V / m

to find the magnetic field we use

           E / B = c

           B = E / c

            B = 375 / 2,9992 10⁸

            B = 1.25 10⁻⁶ T

c) The period is

           T = 1 / f

            T = 1 / 9.50 10¹⁴

            T = 1.05 10⁻¹⁵ s

the wavelength value is

          λ = 3,157 10-7 m (109 nm / 1m) = 315.7 nm

this wavelength corresponds to the ultraviolet

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3 years ago
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3 years ago
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Explanation:

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2 years ago
A nature photographer is using a camera that has a lens with a focal length of 3.06 cm. The photographer is taking pictures of a
sleet_krkn [62]

Answer:

film is at distance of 3.07 cm from lens

Explanation:

Given data

focal length = 3.06 cm

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to find out

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here f = 3.06 and p = 1040 so we find q

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Answer:

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