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Bess [88]
3 years ago
6

Which agent causes sand dunes to form?

Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
6 0
The wind carrying the wind will Crete sand dunes
klasskru [66]3 years ago
3 0

Answer:

C is the answer to your question

You might be interested in
A material has a density of 8.9 g/cm^3. You have 3 grams of the substance. How much space does it take up?
victus00 [196]
Density (d) is the ratio of the substance mass (m) to its volume (v). 
                                     d = m / v
Rearranging the equation gives us the equation for volume which is,
                                      v = m / d
Substituting the values,
                                        v = 3 g / (8.9 g/cm³) 
                                          v = 0.34 cm³
The substance occupies approximately 0.34 cm³.
4 0
3 years ago
“While observing a chemical reaction, how can you tell which reactant is limiting?”
bulgar [2K]

Answer:

Then the substance would be the first to run out which signifies the completing of the reaction.

Explanation:

3 0
3 years ago
The density of mercury is 13.6 g/cm3, What is its density in mg/mm3?
forsale [732]

Answer:

Density of mercury is 13600 kg

8 0
3 years ago
Balance the following equation: N2 + H2 --> NH3
Marina86 [1]

Answer:

3, 2

Explanation:

Balanced equation:

N2 + 3 H2 = 2 NH3

5 0
3 years ago
Find the boiling point?<br> 100. g of C2H6O2 dissolved in 200 g of H2O?
aleksklad [387]

Answer:

The correct answer is 104.13ºC

Explanation:

When a solute is added to a solvent, the boiling point of the solvent (Tb) increases. That is a colligative property. The increment in Tb (ΔTb)  is given by the following expression:

ΔTb = Tb - Tbº= Kb x m

Where Tb and Tbº are the boiling points of the solvent in solution and pure, respectively; Kb is a constant and m is the molality of the solution.

In this problem, the solvent is water (H₂O). It is well known that water has a boiling point of 100ºC (Tb). The value of Kb for water is 0.512ºC/m. So, we have to calculate the molality of the solution (m):

m = moles of solute/Kg solvent

The solute is C₂H₆O₂ and we have to calculate the number of moles of this component by dividing the mass into the molecular weight (Mw):

Mw(C₂H₆O₂)= (2 x 12 g/mol) + (6 x 1 g/mol) + (2 x 16 g/mol)= 62 g/mol

⇒ moles of C₂H₆O₂ = mass/Mw = 100 g/(62 g/mol) = 1.613 moles

Now, we need the mass of solvent (H₂O) in kilograms, so we divide the grams into 1000:

200 g x 1 kg/1000 g = 0.2 kg

Finally, we calculate the molality as follows:

m = 1.613 moles of C₂H₆O₂/0.2 kg = 8.06 moles/kg = 8.06 m

The increment in the boiling point will be:

ΔTb = Kb x m = 0.512ºC/m x 8.06 m = 4.13ºC

So, the boiling point of pure water (Tbº=100ºC) will increase in 4.13ºC:

Tb= 100ºC+4.12ºC= 104.13ºC

5 0
3 years ago
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