Look at figure D . Explain what will happen if a larger mass it put on the force meter
1 answer:
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Answer:
= 19 Ω, I = 0.105 A, V1 = 1.05 V and V2 = 0.95 V
Explanation:
The correct way to solve this type of problem is to find the current or voltage values for the equivalent resistance and from here find the other values.
For a series circuit the equivalent resistance is the sum of the resistance
= R1 + R2
= 10 +9
= 19 Ω
Let's use the equation for the voltage
V = I
I = V /
I = 2/19
I = 0.105 A
In a series circuit the current is constant, so let's use the voltage equation for each resistor
V1 = I R1
V1 = 0.105 10
V1 = 1.05 V
V2 = 0.105 9
V2 = 0.95 V
Note that the sum of this voltage is the total voltage applied.
Answer:
F = 1.19 x 10⁹ N
Explanation:
The electrostatic force between the charged particles is given by Colomb's Law as follows:
where,
F = Electrostatic force = ?
k = Colomb's constant = 9 x 10⁹ N.m²/C²
q₁ = q₂ = charge on proton = 1.6 x 10⁻¹⁹ C
r = distance between protons = 4.4 x 10⁻¹⁰ m
Therefore,
<u>F = 1.19 x 10⁹ N</u>