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devlian [24]
3 years ago
9

Look at figure D . Explain what will happen if a larger mass it put on the force meter

Physics
1 answer:
aev [14]3 years ago
5 0

it will experience great force

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A 2 cm tall object is placed 30cm in front of a concave mirror with focal length of 25 cm. What is the height of the image?
viktelen [127]

Answer:

- 10 cm

Explanation:

h_{o} = height of the object = 2 cm

h_{i} = height of the image

d_{o}  = distance of the object from the mirror = 30 cm  

f  = focal length of the mirror = 25 cm  

d_{i}  = image distance

using the mirror equation

\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}

\frac{1}{30} + \frac{1}{d_{i}} = \frac{1}{25}

d_{i} = 150 cm

using the equation

\frac{h_{i}}{h_{o}} = \frac{- d_{i}}{d_{o}}

\frac{h_{i}}{2} = \frac{- 150}{30}

h_{i} = - 10 cm

8 0
3 years ago
Can someone help me?!!
Fantom [35]
<h2>Hello!</h2>

The answer is:

The first option, the force tending to lift Rover is equal to 14.5 N.

<h2>Why?</h2>

To calculate the force that is tending to lift Rover vertically, we need to calculate the vertical component force.

Since we know that the angle between the force and the ground is 29°, we can calculate the vertical component of the force using the following formula:

F_y=Force*Sin(29\°)

We are given that the force is equal to 30.0 N, so, calculating we have:

F_y=Force*Sin(29\°)

F_y=30N*Sin(29\°)=14.5N

Also, we can calculate the horizontal component of the force using the following formula:

F_x=Force*Cos(29\°)

F_x=30N*Cos(29\°)=26.24N

Hence, we have that the correct option is the first option, the force tending to lift Rover is equal to 14.5 N.

Have a nice day!

5 0
3 years ago
2. How many grams of water can be heated from 20.0°C to 75°C using<br><br><br> 12500.0 Joules?
bogdanovich [222]

Answer:

Grams of water can be heated from 20.0°C to 75°C using  12500.0 Joules = 54.3 g

Explanation:

Heat required to increase temperature

                 H = mcΔT

m = mass of material

C = specific heat of material

ΔT = Change in temperature.

Here we need to find  how many grams of water can be heated from 20.0°C to 75°C using  12500.0 Joules

That is

            H = 12500 J

            Specific heat of water, C = 4186 J/kg°C

            ΔT = 75 - 20 = 55

Substituting

            12500 = m x 4186 x 55

              m = 0.0543 kg

              m = 54.3 g

Grams of water can be heated from 20.0°C to 75°C using  12500.0 Joules = 54.3 g

3 0
3 years ago
Two male moose charge at each other with the same speed and meet on a icy patch of tundra. As they collide, their antlers lock t
Ksenya-84 [330]
Change in velocity of larger moose: (1/3)v - v = -(2/3)v 
<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>
<span>- (change in velocity of larger moose)/(change in velocity of smaller moose) = 2

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.



</span>
4 0
3 years ago
Read 2 more answers
An Elephant is pulled by a group of clowns across a circus. The elephant has a mass of 1000kg and the clowns are pulling with a
GaryK [48]

Answer:

The acceleration of the elephant is 5m/s^2 (squared).

Explanation:

Given: Force=200N, Mass=1000kg

Required: acceleration=?

Equation: a=F/m

Solution: a=200N/1000kg

Answer: a=5m/s^2

5 0
3 years ago
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