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jekas [21]
2 years ago
9

Find the measure of angle RQS.

Mathematics
2 answers:
Natalija [7]2 years ago
6 0

Answer:

137°

Step-by-step explanation:

Because the minor arc formed by ∠SQT has a degree measure of 43, we know that ∠SQT is 43°. Because ∠RQS and ∠SQT are supplementary, ∠RQS = 137°

Helen [10]2 years ago
3 0
I think 137 Degrees
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Successful implementation of a new system is based on three independent modules. Module 1 works properly with probability 0.9, M
olga nikolaevna [1]

Answer:

The probability is 0.5086

Step-by-step explanation:

The probability P that at least one of these three modules will fail to work properly is calculated as:

P = 1 - P'

Where P' is the probability that all the modules works properly. So, P' os calculated as:

P' = 0.9 * 0.84 * 0.65

P' = 0.4914

Because 0.9 is the probability that module 1 works properly, 0.84 is the probability that module 2 works properly and 0.65 is the probability that module 3 works properly.

Finally, the probability P that at least one of these three modules will fail to work properly is:

P = 1 - 0.4914

P = 0.5086

8 0
3 years ago
What is the value of x?
jok3333 [9.3K]

\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{42}{15}

\\ \sf\longmapsto 15x=42(10)

\\ \sf\longmapsto 15x=420

\\ \sf\longmapsto x=\dfrac{420}{15}

\\ \sf\longmapsto x=28

8 0
2 years ago
A ball bearing has mass 0.44 pounds. 1 kg = 2.2 pounds. <br>​
torisob [31]

Answer:

  (i) 0.2 kg

  (ii) kg/cm³

  (b) 2.29 kg

Step-by-step explanation:

This problem gives you relations between units, and the formulas for density and mass. It is asking you to make use of these relations in various mass and density calculations.

<h3>(a)(i)</h3>

The relationship between kg and pounds can be used to write a units conversion multiplier. It will have numerator equal to denominator, but will have units such that multiplying by it will give the units you want.

  0.44 pounds × multiplier = __ kg

  0.44 pounds × (1 kg)/(2.2 pounds) = (0.44/2.2)(1 kg)

  0.44 pounds = 0.2 kg

__

<h3>(a)(ii)</h3>

The formula can be used to find the units of interest:

  Density = mass/volume

  units of density = (units of mass)/(units of volume)

  units of density = kg/cm³

__

<h3>(b)</h3>

Using the given formula with the given value of L, we find the volume to be ...

  V = 4(1.40 cm)(3 -1.40 cm)² = 14.336 cm³

Then the mass is ...

  mass = volume × density

  mass = (14.336 cm³)×(0.160 kg)/(1 cm³) = 2.29376 kg

The mass is about 2.29 kg.

_____

<em>Additional comment</em>

Often you will see density in terms of kg/m³ or g/cm³. Water has a density of about 1 g/cm³ or 1000 kg/m³. The most dense non-radioactive element in the periodic table is osmium, with a density of about 22.6 g/cm³, or 0.0226 kg/cm³. The material in part (b) of this problem has a density about 7 times that, so is clearly not from Earth.

7 0
2 years ago
-3/2(x-2) simplify please
mario62 [17]

Answer:-3x+6/2

Step-by-step explanation:

To simplify -3/2(x-2)

We get

-3x+6/2

4 0
3 years ago
Read 2 more answers
PEOPLE WHO ARE GOOD AT MATH CAN YOU PLEASE HELP ME!!!
OlgaM077 [116]

The cost of using 19 HCF of water is $32.49

Given in the question:

The monthly cost (in dollars) of the water use (in dollars) is a linear function of the amount of water used (in hundreds of cubic feet, HCF)

The cost for using 17 HCF of water is using $32.13

and, the cost of using 35 HCF is $61.83.

To find the cost of using 19 HCF of water.

Now, According to the question:

The cost for using 17 HCF of water is  $32.13

and, the cost of using 35 HCF is $61.83.

To find the slope:

(17, 32.13) and (35, 61.83)

Slope = (61.83 - 32.13)/ (35 - 17) = 1.65

We know that:

Formula of slope :

y = mx + b

32.13 = 1.65 x 17 + b

b = 1.14

The equation will be :

C(x) = 1.65x + 1.14

Now, To find the cost of using 19 HCF of water.

C(19) = 1.65 × 19  + 1.14

C(19) = $32.49

Hence,  the cost of using 19 HCF of water is $32.49.

Learn more about Slopes at:

brainly.com/question/3605446

#SPJ1

6 0
10 months ago
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