Answer:
maximum height on moon is 6 times more than the maximum height on Earth
Explanation:
Let the Astronaut has its maximum speed by which he can jump is "v"
now for the maximum height that it can jump is given as
now from above equation we will have
now we have
now if Astronaut jump on the surface of moon with same speed
then we know that the acceleration of gravity on surface of moon is 1/6 times the gravity on earth
so at surface of moon we have
now we have
so maximum height on moon is 6 times more than the maximum height on Earth
Answer:
o
Explanation:
the increase energy stored in thw system is proportional to the decrease in kinetic energy
Solution
distance travelled by Chris
\Delta t=\frac{1}{3600}hr.
X_{c}= [(\frac{21+0}{2})+(\frac{33+21}{2})+(\frac{55+47}{2})+(\frac{63+55}{2})+(\frac{70+63}{2})+(\frac{76+70}{2})+(\frac{82+76}{2})+(\frac{87+82}{2})+(\frac{91+87}{2})]\times\frac{1}{3600}
=\frac{579.5}{3600}=0.161miles
Kelly,
\Delta t=\frac{1}{3600}hr.
X_{k}=[(\frac{24+0}{2})+(\frac{3+24}{2})+(\frac{55+39}{2})+(\frac{62+55}{2})+(\frac{71+62}{2})+(\frac{79+71}{2})+(\frac{85+79}{2})+(\frac{85+92}{2})+(\frac{99+92}{2})+(\frac{103+99}{2})]\times\frac{1}{3600}
=\frac{657.5}{3600}
\Delta X=X_{k}-X_{C}=0.021miles
