Answer:
Explanation:
When the central shaft rotates , the seat along with passenger also rotates . Their rotation requires a centripetal force of mw²R where m is mass of the passenger and w is the angular velocity and R is radius of the circle in which the passenger rotates.
This force is provided by a component of T , the tension in the rope from which the passenger hangs . If θ be the angle the rope makes with horizontal ,
T cos θ will provide the centripetal force . So
Tcosθ = mw²R
Tsinθ component will balance the weight .
Tsinθ = mg
Dividing the two equation
Tanθ =
Hence for a given w , θ depends upon g or weight .
You are talking about make sure's and pearl substance I thought you was talking about mix in with something
Answer:
<em>-2 units of charge</em>
Explanation:
charge on A = Qa = -6 units
charge on B = Qb = 2 units
if the spheres are brought in contact with each other, the resultant charge will be evenly distributed on the spheres when they are finally separated.
charge on each sphere will be =
charge on each sphere = = = <em>-2 units of charge</em>
Answer:
-5.24 m/s
** The minus sign indicates that the velocity vector points in the opposite direction with respect to the initial direction of the 77.8 kg player **
Explanation:
Hi!
We can solve this problem considering each player as a point particle and taking into account the conservation of linear momentum.
Since the 99.8 kg player is moving towards the 77.8kg, the initial total momentum is:
m1*v1_i + m2*v2_i = (77.8kg)(8.1 m/s) - (99.8kg)(6.9 m/s)
** The minus sign indicates that the velocity vector points in the opposite direction with respect to the initial direction of the 77.8 kg player **
The final total momentum is equal to:
m1*v1_f + m2*v2_f = (77.8 kg)v1_f + (99.8 kg)(3.5 m/s)
The conservation of momentu tell us that:
m1v1_i + m2v2_i = m1v1_f + m2v2_f
Therefore:
v1_f =v1_i + (m2/m1)*(v2_i-v2_f)
v1_f = 8.1 m/s + (99.8 / 77.8) * (-6.9 - 3.5 m/s)
<u>v1_f = -5.24 m/s</u>