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Marizza181 [45]
3 years ago
10

What do colligative properties depend on? A) the identity of the solute b) the number of particles present in the solution c) th

e quantity of solvent in the solution d) none of these
Chemistry
2 answers:
likoan [24]3 years ago
6 0

Answer: b) the number of particles present in the solution

Explanation: Colligative properties are the properties which depends on the amount or the number of particles.

Colligative properties include relative lowering in freezing point,elevation in boiling point, depression in freezing point and osmotic pressure.

\pi =CRT

\pi = osmotic pressure

C= concentration  which depends on the amount or the moles of solute irrespective of its identity.

R= solution constant

T= temperature

Nastasia [14]3 years ago
4 0
B.) Colligative properties depend on <span>the number of particles present in the solution.

Hope this helps!</span>
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3 years ago
How many mol of C7H16 would you have if you have 76.36 grams? Give your answer to 2 decimal spaces.
tensa zangetsu [6.8K]

0.761 mol of C_7H_{16}  would you have if you have 76.36 grams.

<h3>What is a mole?</h3>

A mole is defined as 6.02214076 × 10^{23}of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

Mass=76.36 grams

Moles = \frac{mass}{molar \;mass}

Moles = \frac{76.36 grams}{100.21 g/mol}

Moles = 0.761

Hence,  0.761 mol of  C_7H_{16} would you have if you have 76.36 grams.

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7 0
2 years ago
Why do larger gases such as Neon produce more color bands (line spectra) than smaller gases like Hydrogen?
LekaFEV [45]
Larger gases produces more spectral lines than the smaller gases because they have more orbitals in their atoms.
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3 years ago
Calculate the heat change involved when 2.00 L of water is heated from 20.0/C to 99.7/C in
IgorC [24]

Answer:

669.48 kJ

Explanation:

According to the question, we are required to determine the heat change involved.

We know that, heat change is given by the formula;

Heat change = Mass × change in temperature × Specific heat

In this case;

Change in temperature = Final temp - initial temp

                                       = 99.7°C - 20°C

                                       = 79.7° C

Mass of water is 2000 g ( 2000 mL × 1 g/mL)

Specific heat of water is 4.2 J/g°C

Therefore;

Heat change = 2000 g × 79.7 °C × 4.2 J/g°C

                      = 669,480 joules

But, 1 kJ = 1000 J

Therefore, heat change is 669.48 kJ

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3 years ago
What are some of the forms of energy you used today? How did you use them?
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Answer:

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