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Marizza181 [45]
3 years ago
10

What do colligative properties depend on? A) the identity of the solute b) the number of particles present in the solution c) th

e quantity of solvent in the solution d) none of these
Chemistry
2 answers:
likoan [24]3 years ago
6 0

Answer: b) the number of particles present in the solution

Explanation: Colligative properties are the properties which depends on the amount or the number of particles.

Colligative properties include relative lowering in freezing point,elevation in boiling point, depression in freezing point and osmotic pressure.

\pi =CRT

\pi = osmotic pressure

C= concentration  which depends on the amount or the moles of solute irrespective of its identity.

R= solution constant

T= temperature

Nastasia [14]3 years ago
4 0
B.) Colligative properties depend on <span>the number of particles present in the solution.

Hope this helps!</span>
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A 59.1g sample of aluminum is put into a calorimeter (see sketch at right) that contains 250.0g of water. The aluminum sample st
Rainbow [258]

Answer:

The specific heat capacity of aluminum according to this experiment is 0.863 J/g°C

Explanation:

Step 1: Data given

Mass of aluminium = 59.1 grams

Mass of water = 250.0 grams

Initial temperature of aluminium = 91.3 °C

Initial temperature of water = 16.0 °C

Final temperature = 19.5 °C

Pressure remains constant

Specific heat capacity of water = 4.186 J/g°C

Step 2: Calculate specific heat of aluminium

Heat lost = heat gained

Qlost = -Q heat

Q = m*c*ΔT

heat aluminium = - heat water

m(aluminium) * c(aluminium) * ΔT(aluminium) = -m(water) * c(water) * ΔT(water)

⇒m(aluminium) = mass of aluminium = 59.1 grams

⇒c(aluminium) = the specific heat of aluminium = TO BE DETERMINED

⇒ΔT = the change in temperature = T2 -T2 = 19.5 - 91.3 = -71.8 °C

⇒ m(water) = 250.0 grams

⇒c(water) = the specific heat of water = 4.186 J/g°C

⇒ΔT = the change in temperature = T2 -T2 = 19.5 - 16.0 = 3.5 °C

59.1 * c(aluminium) * -71.8 °C = 250.0 * 4.186 J/g°C * 3.5 °C

c(aluminium) = 0.863 J/g°C

The specific heat capacity of aluminum according to this experiment is 0.863 J/g°C

3 0
3 years ago
Where do the protons and electrons come from that are used in the electron transport chain?
blondinia [14]
The energy generated by the movement of electrons is used to pump electrons across the inner mitochondrial membrane to an area of higher concentration. 17. Where do these protons (H+) come from? The originally came from a glucose molecule and were carried to the electron transport chain by NADH and FADH2.

The answer would be glucose molecule.
5 0
3 years ago
How many h+ ions are present in 65. 5 mL of 0. 722 M sulfuric acid
tangare [24]

Answer:

are there answer options

Explanation:

8 0
2 years ago
An unknown noble gas has a density of 5.84 g dm-3 at STP. Calculate its molar mass, and so identify the gas.
bagirrra123 [75]

The noble gas is Xenon and its molar mass is 131 g/mol.

<h3>What is the molar mass of the noble gas?</h3>

The molar mass of the noble gas is determined as follows;

Let molar mass of unknown gas be M, and mass of gas be m

Density of the noble gas, ρ = 5.8 g/dm³

density = m/V

At STP;

  • temperature, T = 273.15 K
  • pressure, P = 1 atm
  • molar gas constant, R = 0.0821 L.atmK⁻¹mol⁻¹

From ideal gas equation:

PV = nRT

where n = m/M

PV = mRT/M

M = mRT/PV

M =  0.0821 * 273.15 * 5.84/1

Molar mass of the noble gas = 131 g/mol

The noble gas is Xenon which has molar mass approximately equal to 131 g/mol.

Learn more about molar mass at: brainly.com/question/837939

#SPJ1

6 0
1 year ago
An iron bar of mass 841 g cools from 84°C to 7°C. Calculate the heat released (in kilojoules) by the metal.
Oduvanchick [21]

Answer:

28.75211 kj

Explanation:

Given data:

Mass of iron bar = 841 g

Initial temperature = 84°C

Final temperature = 7°C

Heat released = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

specific heat capacity of iron is 0.444 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 7°C - 84°C

ΔT = -77°C

By putting values,

Q = 841 g × 0.444 j/g.°C × -77°C

Q = 28752.11 j

In Kj:

28752.11 j × 1 kJ / 1000 J

28.75211 kj

8 0
3 years ago
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