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svetoff [14.1K]
3 years ago
14

Why the effect of gravitational force is more in liquid than in solid?​

Physics
2 answers:
ICE Princess25 [194]3 years ago
5 0

Explanation:

<em>THE</em><em> </em><em>EFFECT</em><em> </em><em>OF</em><em> </em><em>GRAVITATIONAL</em><em> </em><em>FORCE</em><em> </em><em>IS</em><em> </em><em>MORE</em><em> </em><em>IN</em><em> </em><em>LIQUID</em><em> </em><em>THAN</em><em> </em><em>IN</em><em> </em><em>SOLIDS</em><em>. </em><em>BECAUSE</em><em> </em><em>THE</em><em> </em><em>INTERMOLECULAR</em><em> </em><em>FORCE</em><em> </em><em>IN</em><em> </em><em>LIQUID</em><em> </em><em>ARE</em><em> </em><em>WEAKER</em><em> </em><em>COMPAIRED</em><em> </em><em>TO</em><em> </em><em>THAT</em><em> </em><em>OF</em><em> </em><em>SOLIDS</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

HOPE IT HELP.......❣❣❣

LekaFEV [45]3 years ago
4 0
  • Gravitational force depends only on mass and distance, not on the state of matter.
  • The forces of attraction between molecules in matter are electromagnetic in nature, not gravitational.
  • These attractive forces are stronger in a solid than in a liquid than in a gas.
  • Gravitational forces between molecules is completely negligible compared to the em forces.

So, key answer is inter-molecular forces of solids is stronger than liquids.

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The mass number of a nucleus (except Hydrogen) is: number of protons + number of neutrons.

A=Z+N

A=mass number=protons + neutrons.
Z=atomic number=number of protons.
N=number of neutrons. 

In the case of Hydrogen it depends of isotope of Hydrogen . 
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deuterium:  A=Z+N;   N=1
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3 years ago
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An insulated rigid tank initially contains 1.4-kg saturated liquid water and water vapor at 200°C. At this state, 25 percent of
Elan Coil [88]

Solution:

Mass of liquid water and water vapor in the insulated tank initially = 1.4 kg

Temperature = 200 °C

And 25% of the volume by liquid water is steam.

State 1

$m=\frac{V}{v}$

$m=m_f+m_g$

$1.4=\frac{0.25V}{v_f}+\frac{0.75V}{v_g}$

$1.4=\frac{0.25V}{1.1565 \times 10^{-3}}+\frac{0.75V}{0.1274}$       (taking the value of $v_g$ and $v_g$ at 200°C  )

$V=6.304 \times 10^{-3}$

Now quality of vapor

$x=\frac{m_g}{m}$

  $=3.377 \times 10^{-3}$

Internal energy at state 1 can be found out by

$u_1=u_f+xu_{fg}$

    $=850.65+3.377\times10^{-3}\times 1744.65$

    = 856.54 kJ/kg

After heating with the resistor for 20 minutes, at state 2, the tank contains saturated water vapor $v_2=v_g \text { and }\ x=1$

Tank is rigid, so volume of tank is constant.

$v_g=v_2=\frac{V}{m}$

$v_g=\frac{6.304\times 10^{-3}}{1.4}$

$v_g=4.502 \times 10^{-3} \ m^3 /kg$

Now interpolate the value to get temperature at state 2 with specific volume value to get final temperature

$T_2=360+(374.14-360)\left(\frac{0.004502-0.006945}{0.003155-0.006945}\right)$

   = 369.11° C

Internal energy at state 2

$u_2=2154.9 \ kJ/kg$

Now power rating of the resistor

$P=\frac{m(u_2-u_1)}{t}$

$P=\frac{1.4(2154.9-856.54)}{20 \times 60}$

  = 1.51 kW

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3 years ago
What is the gravitational potential energy of a 2.5kg object that is 300m above the surface of the earth? g=10m/s
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Answer:

7350 J

Explanation:

Gravitational Potential Energy: This is defined as the energy possessed by a body due to it's position in the gravitational field. The S.I unit is Joules(J).

Applying,

E.p = mgh..................... Equation 1

Where E.p = Gravitational potential Energy, m = mass of the object, h = height of the object above the surface of the earth, g = acceleration due to gravity.

Given: m = 2.5 kg, h = 300 m

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Substitute these values into equation 1

E.p = 2.5(300)(9.8)

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3 years ago
A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. T
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The described situation is as follows:

An object is dropped from the top of a tower and when measuring the time it takes to reach the ground that turns out to be 0.02 minutes.

This situation is related to free fall, this also means we have constant acceleration, hence the equations we will use are:

V_{f}=V_{o}+at (1)  

{V_{f}}^{2}={V_{o}}^{2}+2ad (2)  

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V_{f} Is the final velocity of the object

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a=9.8 m/s^{2} is the acceleration due gravity

d is the height of the tower

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b) Begining with (1):

V_{f}=0+at (3)  

V_{f}=at=(9.8 m/s^{2})(1.2 s) (4)  

V_{f}=11.76 m/s (5)  This is the final velocity of the object

a) Substituting (5) in (2):

(11.76 m/s)^{2}=0+2(9.8 m/s^{2})d (6)  

Clearing d:

d=\frac{(11.76 m/s)^{2}}{2(9.8 m/s^{2})} (7)  

d=7.056 m (8)  This is the height of the tower

4 0
3 years ago
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