A simple pendulum of length 1.5m has a bob of mass of 2.0kg, then the period for the small oscillations would be 2.456 s.
<h3>What is the frequency?</h3>
It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.
The frequency of a pendulum is the reciprocal of the time period can be given by the following relation,
f = 1/T
As given in the problem A simple pendulum of length 1.5m has a bob of mass of 2.0kg.
The formula for the time period for the pendulum,
T = 2π√L/g
=2π√1.5/9.81
=2.456 s
Thus, the period for the small oscillations would be 2.456 s.
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Then the the speed of the molecules also increase
Answer: The answer is A.
Explanation:
Suppose you are in an elevator. As the elevator starts upward, its speed will increase. During this time when the elevator is moving upward with increasing speed, your weight will be greater than your normal weight at rest.
Answer:
The speed of the wire is 5 m/s.
Explanation:
Given that,
Length = 20 cm
Magnetic field = 0.1 T
Current = 10 mA
Resistance 
We need to calculate the speed of the wire
Using formula of emf

Using formula of current

Put the value of
into the formula of current




Hence, The speed of the wire is 5 m/s.
Answer:
7772.72N
Explanation:
When u draw your FBD, you realize you have 3 forces (ignore the force the car produces), gravity, normal force and static friction. You also realize that gravity and normal force are in our out of the page (drawn with a frame of reference above the car). So that leaves you with static friction in the centripetal direction.
Now which direction is the static friction, assume that it is pointing inward so
Fc=Fs=mv²/r=1900*15²/55=427500/55=7772.72N
Since the car is not skidding we do not have kinetic friction so there can only be static friction. One reason we do not use μFn is because that is the formula for maximum static friction, and the problem does not state there is maximum static friction.