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svetoff [14.1K]
3 years ago
14

Why the effect of gravitational force is more in liquid than in solid?​

Physics
2 answers:
ICE Princess25 [194]3 years ago
5 0

Explanation:

<em>THE</em><em> </em><em>EFFECT</em><em> </em><em>OF</em><em> </em><em>GRAVITATIONAL</em><em> </em><em>FORCE</em><em> </em><em>IS</em><em> </em><em>MORE</em><em> </em><em>IN</em><em> </em><em>LIQUID</em><em> </em><em>THAN</em><em> </em><em>IN</em><em> </em><em>SOLIDS</em><em>. </em><em>BECAUSE</em><em> </em><em>THE</em><em> </em><em>INTERMOLECULAR</em><em> </em><em>FORCE</em><em> </em><em>IN</em><em> </em><em>LIQUID</em><em> </em><em>ARE</em><em> </em><em>WEAKER</em><em> </em><em>COMPAIRED</em><em> </em><em>TO</em><em> </em><em>THAT</em><em> </em><em>OF</em><em> </em><em>SOLIDS</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

HOPE IT HELP.......❣❣❣

LekaFEV [45]3 years ago
4 0
  • Gravitational force depends only on mass and distance, not on the state of matter.
  • The forces of attraction between molecules in matter are electromagnetic in nature, not gravitational.
  • These attractive forces are stronger in a solid than in a liquid than in a gas.
  • Gravitational forces between molecules is completely negligible compared to the em forces.

So, key answer is inter-molecular forces of solids is stronger than liquids.

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Answer:

A 'kink' in the glass tube which breaks the mercury as it contracts, storing the highest temperature reading. The glass tube is shaped like a lens to magnify the thin mercury thread. Shaking the thermometer resets the mercury back into the bulb.

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A scientist directs monochromatic light toward a single slit in an opaque barrier. The light has a wavelength of 580 nm and the
vredina [299]

Answer:

a) 9.72 mm

b) 4.86 mm

Explanation:

wave length of light  λ is  580 nm = 580 \times 10⁻⁹ m

Width of slit d = 0.215\times 10⁻³ m

Distance of screen D  = 1.8 m.

Width of one fringe = \frac{\lambda\times D}{d}

Putting the values we get fringe width

= \frac{580\times10^{-9}\times1.8}{.000315}

=4.86 mm.

a) Width of central maxima = 2 times width of one fringe

= 2 times 4.86

=9.72 mm

b) width of each fringe except central fringe  is same , no matter what the order is.Only brightness changes .

So width of either of the two first order bright fringe will be same and it will be  

= 4.86 mm.

3 0
3 years ago
Convert 9.75 millimeters to centimeter​
Butoxors [25]

Answer:

0.975cm

Explanation:

7 0
3 years ago
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Explain electric circuits. Be sure to include the features, the roles, and the types. Help PLEASEEEE!!
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If there was any way to do that, then your teacher wouldn't
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3 years ago
A drag racing car with a weight of 1600 lbf attains a speed of 270 mph in a quarter-mile race. Immediately after passing the tim
Kaylis [27]

Answer:

15.065ft

Explanation:

To solve this problem it is necessary to consider the aerodynamic concepts related to the Drag Force.

By definition the drag force is expressed as:

F_D = -\frac{1}{2}\rho V^2 C_d A

Where

\rho is the density of the flow

V = Velocity

C_d= Drag coefficient

A = Area

For a Car is defined the drag coefficient as 0.3, while the density of air in normal conditions is 1.21kg/m^3

For second Newton's Law the Force is also defined as,

F=ma=m\frac{dV}{dt}

Equating both equations we have:

m\frac{dV}{dt}=-\frac{1}{2}\rho V^2 C_d A

m(dV)=-\frac{1}{2}\rho C_d A (dt)

\frac{1}{V^2 }(dV)=-\frac{1}{2m}\rho C_d A (dt)

Integrating

\int \frac{1}{V^2 }(dV)= - \int\frac{1}{2m}\rho C_d A (dt)

-\frac{1}{V}\big|^{V_f}_{V_i}=\frac{1}{2m}(\rho)C_d (\pi r^2) \Delta t

Here,

V_f = 60mph = 26.82m/s

V_i = 120.7m/s

m= 1600lbf = 725.747Kg

\rho = 1.21 kg/m^3

C_d = 0.3

\Delta t=7s

Replacing:

\frac{-1}{26.82}+\frac{1}{120.7} = \frac{1}{2(725.747)}(1.21)(0.3)(\pi r^2) (7)

-0.029 = -5.4997r^2

r = 2.2963m

d= r*2 = 4.592m \approx 15.065ft

4 0
4 years ago
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