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Komok [63]
4 years ago
12

pls help asap Create a Punnett square to model asexual reproduction of bacteria with the dominate trait T, recessive trat t. Cre

ate another Punnett square to model sexual reproduction of the mother Tt, and father TT. In two to three sentences compare and contrast the genetic results of asexual and sexual reproduction. pls help asap
Physics
1 answer:
JulsSmile [24]4 years ago
5 0
Ok you need a punnett square? its gonna be easy, create the square first, Then put the letters in their, When done message me

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a star is seen to have two transiting planets. planet 1 transits every 3 months, and planet 2 transits every 15 months. what can
WINSTONCH [101]
Planet 1 orbits 3x as quick as planet 2
4 0
2 years ago
The velocity of a car teduces from 30 km/h as the car approaches a stop sigh. Is this an example of positive or negative acceler
tresset_1 [31]

<u>Answer:</u>

The stopping car has negative acceleration.

<u>Explanation:</u>

 We know acceleration is the rate of change of velocity. That is

            Acceleration(a) = ( Final velocity - Initial velocity )/ Time taken.

            Here Final velocity = 0 km/h( car stops) and initial velocity = 30 km/h

             So acceleration = (0-30)/time = -30/ time

             Time is always positive , so -30/time is negative, so the stopping car has negative acceleration.

5 0
4 years ago
A 40.0 kg physics student at rest on a frictionless rink throws a 3.0 kg box, giving the box a velocity of 8.0 m/s. Which statem
zvonat [6]

Answer: (b)

Explanation:

Given

mass of Student M=40 kg

mass of box m=3 kg

velocity of box v=8 m/s

suppose u is the velocity of the student after the throw

As there is no external force is applied so momentum is conserved

Initial momentum=final momentum=0

0=Mu+mv

Mu=-mv

u=-\frac{3}{40}\times 8=-\frac{3}{5}\\u=-0.6\ m/s

Here negative sign indicates the velocity is opposite in direction i.e. opposite to the direction of the box

6 0
3 years ago
A)Calculate the effective value of g, the acceleration of gravity, at 7900 m above the Earth's surface.
arsen [322]

The solution for the acceleration of gravity is given as

  • g_{1}=9.789 \mathrm{~m} / \mathrm{s}^{2}$
  • g_2=1.955 \mathrm{~m} / \mathrm{s}^{2}$

This is further explained below.

<h3>What is the effective value of g, the acceleration of gravity, at 7900 km above the Earth's surface.?</h3>

Generally,

Mass of earth $M=5.97 \times 10^{24} \mathrm{~kg}$

Radius of earth $R=6371 \mathrm{~km}$

Gravitational const. $G=6.67 \times 10^{-11} \mathrm{Nm}^{2} \mathrm{~kg}^{-2}$

height $h_{1}=7900 \mathrm{~m}=7.9 \mathrm{~km}$$$

R+h_{1}=6371+7.9 &\\\\R+h_{1}=6378.9 \mathrm{~km} \\\\&R+h_{1}=6378.9 \times 10^{3} \mathrm{~m}\end{aligned}

In conclusion, acceleration due to gravity at this point will be

g_{1}=\frac{G M}{\left(\bar{R}+\overline{h_{1}}\right)^{2}}$\\\\$g_{1}=\frac{6.67 \times 10^{-11} \times 5.97 \times 10^{24}}{\left(6378.9 \times 10^{3}\right)^{2}}$\\\\$g_{1}=9.789 \mathrm{~m} / \mathrm{s}^{2}$

for $h_{2}=7900 \mathrm{~km}$

R+h_{2}=6371+7900\\\\R+h_{2}=14271 \mathrm{~km}\\\\$g_{2}=\frac{6.67 \times 10^{-11} \times 5.97 \times 10^{24}}{\left(14271 \times 10^{3}\right)^{2}}$\\\\$g_2=1.955 \mathrm{~m} / \mathrm{s}^{2}$

Read more about acceleration due to gravity

brainly.com/question/13860566

#SPJ1

5 0
2 years ago
The transferring of electrons keeps ______________ bonds together.
Nikitich [7]
The answer is ionic bonds
3 0
3 years ago
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