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taurus [48]
3 years ago
15

Why are redox reactions used in batteries?

Chemistry
1 answer:
Phoenix [80]3 years ago
5 0

Answer:

Why are redox reactions used in batteries? The attraction between charged ions releases energy. The movement of electrons creates an electric current. The reactions are extremely exothermic, producing an electric current.

Explanation:

Why are redox reactions used in batteries?

The attraction between charged ions releases energy.

The movement of electrons creates an electric current.

The reactions are extremely exothermic, producing an electric current.

The reactions are extremely endothermic, inducing the movement of electrons.

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2 years ago
Write the reaction when solid lead(ii) nitrate is put into water:
Whitepunk [10]
Solid lead nitrate in water gives lead oxide and nitric acid

Pb(NO3)2 + H2O ---> PbO + 2 HNO3
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2 years ago
What is the solution and solvent in Kool-Aid?​
alexandr402 [8]

In this solution the solvent is water and the solutes are sugar, artificial flavor and artificial color. Another interesting property of solutions is that different concentrations of solute can be made. As all of you are aware, you can make very sweet Kool Aid and less sweet Kool Aid.

5 0
2 years ago
Read 2 more answers
State the relationship between electron configuration and location of an element in the period table
inn [45]

Answer:

elements in same group have same valence electron.

period of element is equal to valence shell

Explanation:

if the elements are in a same group then they will be having same number of valence electron.

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5 0
3 years ago
Calculate the volume of compound Y needed to make a 350 pg/ml treatment solution in 2 ml of 1x PBS using a stock solution contai
harina [27]

Answer:

14 mL

Explanation:

To prepare a solution by a concentrated solution, we must use the equation:

C1xV1 = C2xV2, where <em>C</em> is the concentration, <em>V</em> is the volume, 1 is the initial solution and 2 the final solution.

The final solution must have 2 mL and a concentration of 350 pg/mL, and the initial solution has a concentration of 50 pg/mL.

Then:

50xV1 = 350x2

50xV1 = 700

V1 = 700/50

V1 = 14 mL

4 0
3 years ago
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