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Jlenok [28]
3 years ago
13

A golfer badly misjudges a putt, sending the ball only one-quarter of the distance to the hole. The original putt gave the ball

an initial speed of V0. If the force of resistance due to the grass is constant, what would an initial speed in terms of V0 be needed to get the ball to the hole from its original position?
Physics
1 answer:
IRISSAK [1]3 years ago
3 0

Answer:

v = 2 v₀

Explanation:

For this exercise we will use the relationship between work and the change in kinetic energy

          W = ΔK

Where the work is of the friction force, which is always opposed to the movement whereby the angle is 180º

          W = - fr x

The distance for the first case is

         x = 1/4 L

         

We substitute

       -fr ¼ L = ½ m v₀²

        fr L = 2 m v₀²

In the second case, the new speed takes the ball the entire distance

        x = d

        -fr L = ½ m v²

     

We equal the two equations

        2 m v₀² = ½ m v²

        v² = 4 v₀²

        v = 2 v₀

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7 0
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An object is placed 50.0 cm in front of a convex mirror. where can be the image located if the focal length is 40 cm from the mi
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Answer:

Image will form at distance 22.22 cm behind the mirror

Explanation:

As we know that the mirror formula is given as

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now we know that

object distance from mirror is

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now we have

\frac{1}{-50} + \frac{1}{d_i} = \frac{1}{40}

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3 years ago
At what speed would a 3.00 x 10^4 kg airplane have to fly and with a momentum of 1.60 x 10^9 kg.m/s
Ymorist [56]

Answer:

5.3×10⁴ m/s

Explanation:

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V = M/m.................. Equation 2

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3 0
3 years ago
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\% Percent = \frac{4/3 \pi (d_{nucleus}/2)^3}{4/3 \pi (d_{atom}/2)^3}*100

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\% Percent = 7.51*10^{-11}\%

Therefore the percent of the atom's volume is occupied by mass is 7.51*10^{-11}\%

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