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Luba_88 [7]
3 years ago
5

When jogging outside you accidently bump into a curb. Your feet stop but your body continues to move forward and you end up on t

he ground. Which law of motion is being described in this scenario?
Law of Universal Gravitation

Newton’s First Law of Motion

Law of Conservation of Energy

Newton’s Second Law of Motion
Physics
2 answers:
gayaneshka [121]3 years ago
5 0
Newtons first law of motion
object in motion stays in motion, object at rest stays at rest unless acted upon an unbalanced force
VARVARA [1.3K]3 years ago
3 0

Answer:

Newton’s First Law of Motion

Explanation:

When jogging outside you accidentally bump into a curb. Your feet stop but your body continues to move forward and you end up on the ground. Newton's first law of motion is described in this scenario. This is also known as law of inertia.

According to this law, an object at rest will remain at rest and an object in motion will remain in motion until and unless and external force acts on it. In this case, feet stops and body of the person continues to move forward.

Hence, the correct option is (b) " Newton’s First Law of Motion  ".

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Answer:

  1. Na=1
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  3. Br=7
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  6. Sr=2

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viktelen [127]

Answer:

V_d = 1.75 × 10⁻⁴ m/s

Explanation:

Given:

Density of copper, ρ = 8.93 g/cm³

mass, M = 63.5 g/mol

Radius of wire = 0.625 mm

Current, I = 3A

Area of the wire, A = \frac{\pi d^2}{4} = A = \frac{\pi 0.625^2}{4}

Now,

The current density, J is given as

J=\frac{I}{A}=\frac{3}{ \frac{\pi 0.625^2}{4}}= 2444619.925 A/mm²

now, the electron density, n = \frac{\rho}{M}N_A

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N_A=Avogadro's Number

n = \frac{8.93}{63.5}(6.2\times 10^{23})=8.719\times 10^{28}\ electrons/m^3

Now,

the drift velocity, V_d

V_d=\frac{J}{ne}

where,

e = charge on electron = 1.6 × 10⁻¹⁹ C

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V_d=\frac{2444619.925}{8.719\times 10^{28}\times (1.6\times 10^{-19})e} = 1.75 × 10⁻⁴ m/s

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