Answer:
60.55%
Explanation:
nO3=155/48
nO2 used: 3/2nO3=4.84375
percent yield: 4.84375/8=60.55%
Answer:

Explanation:
25. Boyle's Law
The temperature and amount of gas are constant, so we can use Boyle’s Law.

Data:

Calculations:

26. Ideal Gas Law
We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.
pV = nRT
Data:
p = 101.3 kPa
V = 20 L
n = 5 mol
R = 8.314 kPa·L·K⁻¹mol⁻¹
Calculation:
101.3 × 20 = 5 × 8.314 × T
2026 = 41.57T

D) There is a large, apelike creature living in the Himalayas is a scientific statement. The other statements are basically opinions.
Hope this Helps!!
Answer:
4.90 moles of
will produce (9.8) moles of
,
(4.90) moles of
and
(39.2) moles of 
Explanation:
From the question we are told that
The number of moles of is 
The formation reaction of
is
From the reaction we see that
1 mole of
is formed by 2 moles of
1 mole of
and 4 
This implies that
4.90 moles of
will produce (2 * 4.90) moles of
,
(1 * 4.90) moles of
and
(8 * 4.90) moles of 
So
4.90 moles of
will produce (9.8) moles of
,
(4.90) moles of
and
(39.2) moles of 