Answer: 20.2 m/s
Explanation:
From the question above, we have the following data;
M1 = 800kg
M2 = 1200kg
V1 = 13m/s
V2 = 25m/s
U (common velocity) =?
M1V1 + M2V2 = (M1 + M2). U
(800*13) + (1200*25) = (800+1200) * U
10400 + 30000 = 2000u
40400 = 2000u
U = 40400 / 2000
U = 20.2 m/s
Answer:
7.39 m or 3.61 m
Explanation:
= Wavelength
f = Frequency = 90 Hz
v = Speed of sound = 340 m/s
Path difference of the two waves is given by
![s_1-s_2=\frac{\lambda}{2}](https://tex.z-dn.net/?f=s_1-s_2%3D%5Cfrac%7B%5Clambda%7D%7B2%7D)
Velocity of wave
![v=f\lambda\\\Rightarrow \lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{340}{90}\\\Rightarrow \lambda=3.78\ m](https://tex.z-dn.net/?f=v%3Df%5Clambda%5C%5C%5CRightarrow%20%5Clambda%3D%5Cfrac%7Bv%7D%7Bf%7D%5C%5C%5CRightarrow%20%5Clambda%3D%5Cfrac%7B340%7D%7B90%7D%5C%5C%5CRightarrow%20%5Clambda%3D3.78%5C%20m)
![s_1=s_2\pm\frac{\lambda}{2}\\\Rightarrow s_1=5.5\pm \frac{3.78}{2}\\\Rightarrow s_1=7.39\ m, 3.61\ m](https://tex.z-dn.net/?f=s_1%3Ds_2%5Cpm%5Cfrac%7B%5Clambda%7D%7B2%7D%5C%5C%5CRightarrow%20s_1%3D5.5%5Cpm%20%5Cfrac%7B3.78%7D%7B2%7D%5C%5C%5CRightarrow%20s_1%3D7.39%5C%20m%2C%203.61%5C%20m)
So, the location from the worker is 7.39 m or 3.61 m
Answer: Radio waves have the lowest energies, longest wavelengths, and lowest frequencies of any type of EM radiation. In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.
Explanation:
Answer:
The slope of a position-time graph represents an object’s velocity.
Explanation:
In a position-time graph, the values on the x-axis represent the time, while the values on the y-axis represent the position of the object.
Velocity is defined as the ratio between the displacement of an object and the time taken:
![v=\frac{\Delta s}{\Delta t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B%5CDelta%20s%7D%7B%5CDelta%20t%7D)
However, we can see that this definition corresponds to the slope of the curve in a position-time graph. In fact:
, the displacement, corresponds to the difference in position, so the difference between the values on the y-axis: ![\Delta s=y_2 -y_1](https://tex.z-dn.net/?f=%5CDelta%20s%3Dy_2%20-y_1)
, the time interval, corresponds to the difference in times, so the difference between the values on the x-axis: ![\Delta t= t_2 -t_1=x_2 -x_1](https://tex.z-dn.net/?f=%5CDelta%20t%3D%20t_2%20-t_1%3Dx_2%20-x_1)
So, the velocity is
![v=\frac{\Delta s}{\Delta t}=\frac{y_2 -y_1}{x_2 -x_1}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B%5CDelta%20s%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7By_2%20-y_1%7D%7Bx_2%20-x_1%7D)
which corresponds to the slope of the curve.
Answer:
The Normal and Gravitational Force
Explanation:
The normal force pushes up and is between the ground and the scale. The gravitational force is the force exerted on the ground.