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Virty [35]
3 years ago
9

How did people years ago find out which side of a magnet was north and which was south?

Physics
1 answer:
wlad13 [49]3 years ago
5 0
In 1600 when William Gilbert published De Magnete
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The magnitude of the magnetic field that a long and extremely thin current-carrying wire produces at a distance of 3.0 µm from t
Reil [10]

Answer:

Current (I) = 3 x 10^-2 A

Explanation:

As we know, B = 4\pi 10^-7 *l/ 2\pi r

By putting up the values needed from the data...

Current (I) = 2 x 3.14 x (3.0 x 10^-6) (2.0 x 10^-3) / 4 x 3.14 x 10^-7 = 3 x 10^-2 A

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3 years ago
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Alexandra knows that the atomic number of the element potassium, K, is 19. She also knows that one particular isotope of potassi
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3 years ago
A penny is dropped from the top of a tower. It hits the ground below after 2.5 s. How tall was the tower?
pychu [463]

Answer:

C. 30.6m

Explanation:

To find the height of the tower, we are to use Newtons law of motion to solve this problem. Since the penny is falling from the top of the tower, it is acted by the acceleration due to gravity. The formula to be used is:

H=ut+\frac{1}{2}gt^2

Where H is the height of the tower, t is the time taken to hit the ground, u is the initial velocity and g is the acceleration due to gravity.

Given that, t = 2.5 s, g =9.8 m/s², u = 0 m/s (at the top of tower)

H=ut+\frac{1}{2}gt^2\\\\H=0(2.5)+ \frac{1}{2}(9.8)(2.5)^2\\\\H=30.6\ m

3 0
3 years ago
Answer fast !!!!!!! pleaseee
wariber [46]

Answer: Magnetic Fields

Explanation:

ig

5 0
2 years ago
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A positive charge is moved from point A to point B along an equipotential surface. How much work is performed or required in mov
Nitella [24]

Answer:

No work is performed or required in moving the positive charge from point A to point B.

Explanation:

Lets take

Q= Positive charge which move from  point A to point B along

Voltage difference,ΔV =V₁ - V₂  

The work done

W = Q . ΔV

Given that  charge is moved from point A to point B along an equipotential surface.It means that voltage  difference is zero.

ΔV = 0

So

W = Q . ΔV

W = Q x 0

W= 0 J

So work is zero.

5 0
3 years ago
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