Answer:
4.08 × 10⁻³
Explanation:
Step 1: Write the balanced reaction at equilibrium
NH₄I(s) ⇄ NH₃(g) + HI(g)
Step 2: Calculate the equilibrium constant
The equilibrium constant (K) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. Only gases and aqueous species are included.
![K = [NH_3] \times [HI] = 4.34 \times 10^{-2} \times 9.39 \times 10^{-2} = 4.08 \times 10^{-3}](https://tex.z-dn.net/?f=K%20%3D%20%5BNH_3%5D%20%5Ctimes%20%5BHI%5D%20%3D%204.34%20%5Ctimes%2010%5E%7B-2%7D%20%20%5Ctimes%209.39%20%5Ctimes%2010%5E%7B-2%7D%20%3D%204.08%20%5Ctimes%2010%5E%7B-3%7D)
PH=-log[H+]
pH=-log(1.4x10^-5)
pH=4.85
The volume of the oxygen gas at standard temperature is 41.36 liters.
The given parameters;
- <em>initial volume of oxygen, V₁ = 45 L</em>
- <em>temperature of oxygen, T₁ = 24 ⁰C = 297 K</em>
- <em>standard temperature, T₂ = 0 ⁰C = 273 K</em>
<em />
The volume of the oxygen gas at standard temperature is determined by applying Charles law as shown below;
Thus, the volume of the oxygen gas at standard temperature is 41.36 L.
Learn more here:brainly.com/question/16927784
Answer:
2 HCl + CaCO3 = CaCl2 + H2O + CO2
Explanation:
On the right side we have 2xCl, to get the same amount we will multiply HCl on the left side by 2.
This will give us 2xH on the left side; we also have 2xH on the right side ( in H2O).
On both sides we have 1x Ca; 1x C.
On the left side we have 3XO (in CaCO3), on the right side we have 1O in H20 and 2xO in CO2, so 3x O on the right side as well.
The reaction is balanced.
1.0153 x 10^3
essentially, scientific notation requires you to take a very large or very small number and simplify it into the first few digits times 10 raised to the power of x.
Although realistically, there is no practical reason to simplify a number that is already that close to 1.
