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svlad2 [7]
2 years ago
10

Estimate the kinetic energy (in GJ) of a 98,000 metric ton aircraft carrier moving at a speed of at 32 knots. You will need to l

ook up the definition of a nautical mile to use in converting the unit for speed, where 1 knot equals 1 nautical mile per hour.
Physics
1 answer:
kiruha [24]2 years ago
8 0

Answer:

K = 13.276 GJ

Explanation:

Given:

Mass of the aircraft (m) = 98,000 metric ton

Speed of the aircraft (v) = 32 knots

Kinetic energy of the aircraft (K) = ?

We know that,

1 metric ton = 1000 kg

∴ 98,000 metric ton = 98,000 × 1000 = 9.8 × 10⁷ kg

Also, 1 knot = 1 nautical mile per hour

So, 32 knots = 32 nautical miles per hour

Converting nautical miles per hour to meter per second using the following conversions, we get:

1 nautical mile = 1852 m

1 hour = 3600 s

Therefore, 1 nautical mile per hour = \frac{1852}{3600}\ m/s

So, 32 nautical miles per hour = 32\times \frac{1852}{3600}=16.46\ m/s

Therefore, the mass and speed of the aircraft are:

m=9.8\times 10^{7}\ kg\\v=16.46\ m/s

Now, kinetic energy is given as:

K=\frac{1}{2}mv^2

Plug in the above values and solve for 'K'. This gives,

K=\frac{1}{2}\times 9.8\times 10^7\times (16.46)^2\\\\K=4.9\times 270.9316\times 10^7\ J\\\\K=13.276\times 10^2\times 10^7\ J\\\\K=13.276\times 10^9\ J

Now, we know that, 1 GJ = 10⁹ J

Therefore, the value of 'K' in terms of GJ is given as:

K = 13.276 GJ

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Answer:

Resistance training.

Explanation:

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2 years ago
Anna will wear a black dress when she attends her cousin’s wedding. Which color(s) does the dress absorb?
storchak [24]
As the dress is black it will absorb all colors with all different wavelengths

In short, Your Answer would be Option A

Hope this helps!
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3 years ago
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What are some properties of transverse waves?
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2 years ago
A charged particle is moving in a uniform magnetic field at a speed of 8.2Ã10^3 m/s in a direction 87° from the direction of th
77julia77 [94]

Answer:

Magnetic field, B = 0.042 T

Explanation:

It is given that,

Speed of charged particle, v=8.2\times 10^3\ m/s

Angle between velocity and the magnetic field, \theta=87

Charge, q=5.7\ \mu C=5.7\times 10^{-6}\ C

Magnetic force, F = 0.002 N

The magnetic force is given by :

F=qvB\ sin\theta

B is the magnetic field  

B=\dfrac{F}{qv\ sin\theta}

B=\dfrac{0.002}{5.7\times 10^{-6}\times 8.2\times 10^3\times sin(87)}

B = 0.042 T

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5 0
3 years ago
When a 0.622 kg basketball hits the floor, its velocity changes from 4.23 m/s down to 3.85 m/s up. If the ball was in contact wi
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when the ball hits the floor and bounces back the momentum of the ball changes.

the rate of change of momentum is the force exerted by the floor on it.

the equation for the force exerted is

f = rate of change of momentum

f = \frac{mv - mu}{t}

v is the final velocity which is - 3.85 m/s

u is initial velocity - 4.23 m/s

m = 0.622 kg

time is the impact time of the ball in contact with the floor - 0.0266 s

substituting the values

f = \frac{0.622 kg (3.85 m/s - (-)4.23 m/s)}{0.0266}

since the ball is going down, we take that as negative and ball going upwards as positive.

f = 189 N

the force exerted from the floor is 189 N

4 0
3 years ago
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