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3 years ago

Tracy scuffs her socked feet across a carpet. When she touches a doorknob, she gets a small shock.

Physics

2 answers:

lubasha [3.4K]3 years ago

6 0

I believe the answer would be B.

Brut [27]3 years ago

6 0

Answer:

Correct answer is b(Through friction between her feet and the carpet)

Explanation:

Whenever we rub our body against carpet or any other object made of fiber materials that time frictional force act. Due to frictional force our body get some extra electron.

When Tracy scuff her feet across a carpet, That time due to friction between her feet and carpet she got some extra electrons. These Electrons can move easily through conductor. When Tracy touched the doorknob which is made up of some metal(conductor) and has positive charge that time extra electrons moved from Tracy to the knob. Due to quick movement of electrons Tracy gets a small shock.

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Write a script that depicts an employer meeting expectation and failing meeting expectations

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2 years ago

What is the toy's total energy at any point of its motion? Express your answer with the appropriate units.]

suter [353]

The complete question is as follows:

A 0.150-kg toy is undergoing SHM on the end of a horizontal spring with force constant k = 300 N/m. When the toy is 0.0120 m from its equilibrium position, it is observed to have a speed of 0.400 m/s.

Answer:

The correct answer is 0.034 J.

Explanation:

Given :

mass of the toy is m = 0.15 kg.

The force constant of restoring force k = 300 Nm⁻¹

When the position of the toy from the equilibrium is x = 0.012m, then the

speed of the toy vx = 0.4m s

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E= 1/2 (mv²+ kx²) = 1/2 kA²

(here, m = mass of the object, vx = velocity, k = force constant

of restoring force, and A = amplitude of SHM.)

Hence by substituting the numerical values in equation 1, we get

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3 years ago

Two small frogs simultaneously leap straight up from a lily pad. Frog A leaps with an initial velocity of 0.551 m/s, while frog

goblinko [34]

Answer:

d = .076 m

Explanation:

The time for frog A can be calculated from equation of motion

$v_f = v_o + at$

where v_f is final velocity, a is acceleration due to gravity

so from given data we have

$-0.551= 0.551 + (-9.8)(t)$

t = 0.112 sec

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$v_f = 0.128 m/s$ (Note its positive)

For the displacement

$s = v_o t + 0.5at^2$

$s = (1.23)(0.112) + (.5)(-9.8)(0.112)^2$

d = .076 m

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