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3 years ago

Tracy scuffs her socked feet across a carpet. When she touches a doorknob, she gets a small shock.

Physics

2 answers:

lubasha [3.4K]3 years ago

6 0

I believe the answer would be B.

Brut [27]3 years ago

6 0

Answer:

Correct answer is b(Through friction between her feet and the carpet)

Explanation:

Whenever we rub our body against carpet or any other object made of fiber materials that time frictional force act. Due to frictional force our body get some extra electron.

When Tracy scuff her feet across a carpet, That time due to friction between her feet and carpet she got some extra electrons. These Electrons can move easily through conductor. When Tracy touched the doorknob which is made up of some metal(conductor) and has positive charge that time extra electrons moved from Tracy to the knob. Due to quick movement of electrons Tracy gets a small shock.

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Consider the following three statements: (i) For any electro-magnetic radiation, the product of the wavelength and the frequency

Scilla [17]

Answer:

A and B

Explanation:

The relation between frequency and wavelength is shown below as:

$c=frequency\times Wavelength$

c is the speed of light having value $3\times 10^8\ m/s$

Thus, the product of the wavelength and the frequency is constant and equal to $3\times 10^8\ m/s$

Option A is correct.

Given, Frequency = $1\times 10^{18}\ Hz$

Thus, Wavelength is:

$Wavelength=\frac{c}{Frequency}$

$Wavelength=\frac{3\times 10^8}{1\times 10^{18}}\ m$

$Wavelength=3\times 10^{-10}\ m$

Also, 1 m = $3\times 10^{-10}$ Å

So,

Wavelength = 3.0 Å

Option B is correct.

As stated above, the speed of electromagnetic radiation is constant. Hence, each radiation of the spectrum travels with same speed.

Option C is incorrect.

3 0

3 years ago

Read 2 more answers

A 1.1 kg ball is attached to a ceiling by a 2.16 m long string. The height of the room is 5.97 m . The acceleration of gravity i

nydimaria [60]

1. -23.2 J

The gravitational potential energy of the ball is given by

$U=mgh$

where

m = 1.1 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration of gravity

h is the height of the ball, relative to the reference point chosen

In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is

h = -2.16 m

And the gravitational potential energy is

$U=(1.1 kg)(9.8 m/s^2)(-2.16 m)=-23.2 J$

2. 41.1 J

Again, the gravitational potential energy of the ball is given by

$U=mgh$

In this part of the problem, the reference point is the floor.

The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:

h = 5.97 m - 2.16 m = 3.81 m

And so the gravitational potential energy of the ball relative to the floor is

$U=(1.1 kg)(9.8 m/s^2)(3.81 m)=41.1 J$

3. 0 J

As before, the gravitational potential energy of the ball is given by

$U=mgh$

Here the reference point is a point at the same elevation of the ball.

This means that the heigth of the ball relative to that point is zero:

h = 0 m

And so the gravitational potential energy is

$U=(1.1 kg)(9.8 m/s^2)(0 m)=0 J$

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