Tracy scuffs her socked feet across a carpet. When she touches a doorknob, she gets a small shock.
2 answers:
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Answer:
the final temperature of the tea is 7.39⁰C.
Explanation:
Given;
mass of the tea, m = 375 g
specific heat capacity of the tea, C = 4.184 JJ/g°C
initial temperature of the tea, t₁ = 95°C
the final temperature of the tea, t₂ = ?
Energy lost by the refrigerator, Q = 137,460 J
The energy lost by the refrigerator is given by the following formula;
-Q = mc(t₂ - t₁)
-137,460 =375 x 4.184(t₂ - 95°C)
-137,460 = 1569(t₂ - 95°C)
Therefore, the final temperature of the tea is 7.39⁰C.
The pressure exerted by the block on the table is given by:
where W is the weight of the box, and A is the bottom surface area of the box.
The weight of the box is:
Substituting into the first equation, we find the pressure: