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vlabodo [156]
3 years ago
12

How to make crystals using table salt? Please help I"ll mark you as the BRAINLIEST!!!

Chemistry
1 answer:
Dafna11 [192]3 years ago
8 0

Answer:

1.heat a pan of water with just a little bit of water,have a boil

2.chosse ure salt

3.stir in has much salt has u can than take the pan off the heat

4.pour the mix into a glass jar

5.tie a string to an objeet that can lay accross the top and put just the string in ure mix

Explanation oh and look at it everyday       hope that helps

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How many moles of calcium chloride, cacl2, can be added to 1.5 l of 0.020 m potassium sulfate, k2so4, before a precipitate is ex
Brut [27]
When CaSO4 → Ca2+ + SO4
So when we have Ksp = [Ca2+][SO4]

when Ksp = 4.93 x 10^-5
and [SO4] = 0.02 M 
so by substitution we can get [Ca2+] 
4.93x10^-5 = [Ca2+] [0.02]
∴ [Ca2+] = 0.0025 mol/L

∴ the moles of calcium chloride = 0.0025 mol / L * 1.5 L
                                                      = 0.00167 mol

4 0
3 years ago
The force of a gas's outward push divided by the area of the walls of the container is the gas's
PilotLPTM [1.2K]
That is the definition of pressure.  The amount of force exerted over a certain area: N/m^2 (Newtons per square metre).
5 0
3 years ago
Read 2 more answers
A
Mnenie [13.5K]

Answer:

it should be the second one since London dispersion causes interaction between molecules.

hope I helped.

6 0
2 years ago
A substance that contains only one type of particle is an __________​
Dvinal [7]

the answer is a chemical element

7 0
3 years ago
Read 2 more answers
General Chemistry fourth edition by McQuarrie, Rock, and Gallogly. University Science Books presented by Macmillan Learning.
Helen [10]

Answer:

3.07 Cal/g

Explanation:

Step 1: Calculate the heat absorbed by the calorimeter

We will use the following expression.

Q = C × ΔT

where,

  • Q: heat absorbed
  • C: heat capacity of the calorimeter (37.60 kJ/K = 37.60 kJ/°C)
  • ΔT: temperature change (2.29 °C)

Q = 37.60 kJ/°C × 2.29 °C = 86.1 kJ

According to the law of conservation of energy, the heat released by the candy has the same magnitude as the heat absorbed by the calorimeter.

Step 2: Convert 86.1 kJ to Cal

We will use the conversion factor 1 Cal = 4.186 kJ.

86.1 kJ × 1 Cal/4.186 kJ = 20.6 Cal

Step 3: Calculate the number of Cal per gram of candy

20.6 Cal/6.70 g = 3.07 Cal/g

3 0
3 years ago
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