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RideAnS [48]
3 years ago
15

Expressed in the correct number of significant figures the sum of 0.53 cm + 75.321 cm + 28.1 cm =

Chemistry
1 answer:
Nadya [2.5K]3 years ago
5 0

Answer:

\boxed{\text{104.0 cm}}

Explanation:

When adding or subtracting values, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.  

That is, you round off to the same number of decimal places as the measurement with the fewest decimal places.

\begin{array}{r|l}0.5& \text{3 cm}\\+ 75.3& \text{21 cm}\\+ 28.1 & \quad\text{cm} \\= 103.9 &\text{51 cm}\\\end{array}

The measurement of 28.1 cm has one digit after the decimal point, so you round the sum to have only one digit to the right of the decimal.

However, the number to be dropped (51) is greater than 5 with only zeros or nothing following the 5.

You must round up the answer. You increase the last significant digit by one.

\text{The sum is $\boxed{\textbf{104.0 cm}}$}

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umka2103 [35]

Based on the data given in this question, the statement that shows a correct interpretation of the chemical reactions is as follows: reaction A was exothermic and reaction B was endothermic.

<h3>What are endothermic and exothermic reactions?</h3>

Endothermic reaction is a chemical reaction that absorbs heat energy from its surroundings while exothermic reaction is a reaction that releases energy in the form of heat.

Endothermic reactions leave their surroundings cooler while exothermic reactions leave their surroundings hotter.

According to this question, the initial and final temperatures of two reactions are given as follows:

  • Reaction A: 25.1°C and 30.2°C
  • Reaction B: 25.1°C and 20.0°C

From the above data, reaction A was exothermic because it increased the surrounding temperature and reaction B was endothermic because it reduced the surrounding's temperature.

Learn more about endothermic and exothermic at: brainly.com/question/23184814

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4 0
2 years ago
1 point If the boy is pushing with 50N of force and the static friction resistance is 70N of force, what will happen? *​
solniwko [45]
Nothing, he shouldn’t be able to move it. Think about it like this say you try really hard to push something that is 5,000 pounds and you push as hard as you can. Well you can’t move it bc it weighs more than you can push. I’m sure their is a equation you can use to see how much you can push (body weight=force?)
6 0
3 years ago
What mass of zinc (molar mass 65.4 g moll) does it take to produce 0.50 mole of H2(g)?
Hatshy [7]

Answer:

32.7 g of Zn

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + 2HCl —> ZnCl₂ + H₂

From the balanced equation above,

1 mole of Zn reacted to produce 1 mole of H₂

Next, we shall determine the number of mole of Zn required to produce 0.5 mole of H₂. This can be obtained as follow:

From the balanced equation above,

1 mole of Zn reacted to produce 1 mole of H₂.

Therefore, 0.5 mole of Zn will also react to produce to 0.5 mole of H₂.

Thus, 0.5 mole of Zn is required.

Finally, we shall determine the mass of 0.5 mole of Zn. This can be obtained as follow:

Mole of Zn = 0.5 mole

Molar mass of Zn = 65.4 g/mol

Mass of Zn =?

Mass = mole × molar mass

Mass of Zn = 0.5 × 65.4

Mass of Zn = 32.7 g

Thus, 32.7 g of Zn is required to produce 0.5 mole of H₂.

4 0
2 years ago
What does mass change to and what does it do
Nataly [62]

Answer:

Mass is the amount of matter in an object and does not change with location.

Explanation:

4 0
3 years ago
15.0 g of cream at 10.0 ℃ are added to an insulated cup containing 150.0 g of coffee at 78.6 °C. Calculate the equilibrium tempe
elena-14-01-66 [18.8K]

Answer:

The equilibrium temperature of the coffee is 72.4 °C

Explanation:

Step 1: Data given

Mass of cream = 15.0 grams

Temperature of the cream = 10.0°C

Mass of the coffee = 150.0 grams

Temperature of the coffee = 78.6 °C

C = respective specific heat of the substances( same as water) = 4.184 J/g°C

Step 2: Calculate the equilibrium temperature

m(cream)*C*(T2-T1) = -m(coffee)*c*(T2-T1)

15.0 g* 4.184 J/g°C *(T2 - 10.0°C) = -150.0g *4.184 J/g°C*(T2-78.6°C)

62.76T2 - 627.6 = -627.6T2 + 49329.36

690.36T2 = 49956.96

T2 = 72.4 °C

The equilibrium temperature of the coffee is 72.4 °C

7 0
3 years ago
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