The % V/V concentration of a 180-mL disinfectant solution containing 85 mL of isopropyl alcohol is 47 % V/V.
<h3>What is the % V/V concentration?</h3>
It refers to the milliliters of solute for every 100 milliliters of solution.
We have 180 mL of a disinfectant solution that contains 85 mL of isopropyl alcohol (solute).
The % V/V concentration of this solution is:
% V/V = (mL solute/mL solution) × 100% =
% V/V = (85 mL/180 mL) × 100% = 47% V/V
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Answer:
1.389 moles
Explanation:
We are given that
Given mass of ammonium=25.0 g
We have to find the number of moles in 25.0g of ammonium.
The chemical formula of ammonium 
Molar mass of N=14, Molar mass of H=1
Molar mass of ammonium (NH4+)=14+4(4)=18 g/mol
We know that
Number of moles=Given mass/Molar mass
Using the formula
Number of moles of ammonium=
moles
Number of moles of ammonium=1.389 moles
Hence, the number of moles in 25.0g of ammonium=1.389 moles
<span>Answer:
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