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GREYUIT [131]
2 years ago
5

Max ran 100 feet in 10 seconds.

Physics
2 answers:
Ivanshal [37]2 years ago
8 0

Answer:

for max :

100 feet in 10 secs

for molly :

60 feet in 5 secs = 120 feet in 10 secs

so, molly ran farther in the same time interval i.e. covered 120 feet where as Max covered 100 feet

Explanation:

brainliest plz

Pani-rosa [81]2 years ago
5 0

Answer:

1 no Max

2 no Molly

Explanation:

because if molly can run 60 feet in 5 second he can run 120 feet in 10 second

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Mike Powell holds the record for the long jump of 8.95 m, established in 1991. If he left the ground at an angle of 18.8°, what
maksim [4K]

Answer:

<em>12 m/s</em>

Explanation:

<u>Projectile Motion</u>

It's also known as 2D motion because the movement takes place in both axis x and y. The x-axis motion is at a constant speed since in absence of friction, no external force stops or accelerates the object. The y-axis motion is at variable speed, which is changed by the acceleration of gravity that makes the object to reach a maximum height and then go back to ground level.

The maximum horizontal distance reached (also called Range) is given by

\displaystyle X_m=\frac{V_{o}^2sin2\theta}{g}

Knowing that \theta=18.8^o, X_m=8.95\ m, we solve for Vo

\displaystyle V_o=\sqrt{\frac{gX_m}{sin2\theta}}

\displaystyle V_o=\sqrt{\frac{9.8\cdot 8.95}{sin(2\cdot 18.8^o)}}=12\ m/s

Thus, the initial speed of Mike Powell was 12 m/s

7 0
3 years ago
Which condition would cause salinity of ocean water to decrease
diamong [38]

D. A river flowing into the sea

The freezing of glaciers would do nothing to the salinity. Hot weather on the other hand, and evaporation, would leave behind the salt and thus it Increases the amount of salt to water in the ocean.  

3 0
3 years ago
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A 50 mm diameter steel shaft and a 100 mm long steel cylindrical bushing with an outer diameter of 70 mm have been incorrectly s
BARSIC [14]

Answer:

The axial force is  P =  15.93 k N

Explanation:

From the question we are told that

     The diameter of the shaft steel is  d =  50mm

      The length of the cylindrical bushing  L =100mm

     The outer diameter of the cylindrical bushing  is  D =  70 \ mm

       The diametral interference is \delta _d = 0.005 mm

       The coefficient of friction is  \mu = 0.2

       The Young modulus of  steel is  207 *10^{3} MPa (N/mm^2)

The diametral interference is mathematically represented as

           \delta_d = \frac{2 *d * P_B * D^2}{E (D^2 -d^2)}

Where P_B is the pressure (stress) on the two object held together  

     So making P_B the subject

            P_B = \frac{\delta _d E (D^2 - d^2)}{2 * d* D^2}

Substituting values

                P_B = \frac{(0.005) (207 *10^{3} ) * (70^2 - 50^2))}{2 * (50) (70) ^2 }

                 P_B = 5.069 MPa

Now he axial force required is

             P =  \mu * P_B * A

Where A is the area which is mathematically evaluated as

               \pi d l

So   P  =  \mu P_B \pi d l

Substituting values

      P =  0.2 * 5.069 * 3.142 * 50 * 100

       P =  15.93 k N

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What provides the centripetal force needed to keep Earth in orbit?
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option C ............

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postnew [5]

Answer:

400N

Explanation:

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3 years ago
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