Answer:
specific gravity = 0.8
specific gravity of solution = 2
Explanation:
given data
rectangular block above water = 0.400 in
rectangular block below water = 1.60 in
material floats below water = 0.800 in
solution
first we get here specific gravity of block that is
specific gravity = block vol below ÷ total block vol × specific gravity water ..............1
put here value we get
specific gravity =
× 1
specific gravity = 0.8
and now we get here specific gravity of solution that is express as
specific gravity of solution = total block vol ÷ block vol below × specific gravity block ........................2
put here value we get
specific gravity of solution =
× 0.8
specific gravity of solution = 2
Answer:
W2 = W1
Explanation:
work is independent of the path taken between the points.
Answer:
The value is
Explanation:
From the question we are told that
The length of the crack is
The frequency is
The distance outside the cave that is being consider is
The speed of sound is 
Generally the wavelength of the wave is mathematically represented as

=> 
=> 
Generally for a single slit the path difference between the interference patterns of the sound wave and the center is mathematically represented as

=> 
=> 
Generally the width of the sound beam is mathematically represented as

=> 
=>