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3 years ago

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A supply plane needs to drop a package of food to scientists working on a glacier in Greenland. The plane flies 90.0 m above the

glacier at a speed of 180 m/s . You may want to review (Pages 86 - 90) . For help with math skills, you may want to review: Mathematical Expressions Involving Squares For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Dock jumping. Part A How far short of the target should it drop the package? Express your answer using three significant figures with the appropriate units.

1 answer:

romanna [79]3 years ago

6 0

Answer:

d = 771.3m

Explanation:

Let's first calculate the time of flight:

$Yf = Yo+Voy*t-g*t^2/2$ where Voy=0. Solving for t:

$t = \sqrt{2*90/9.8} =4.285s$

Now we calculate the horizontal displacement, wihch is the distance from the target to drop the package:

Xf = d = Vox*t

d = 180*4.285 = 771.3m

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Two engineering students, John with a weight of 92 kg and Mary with a weight of 46 kg, are 30 m apart. Suppose each has a 0.04%

Hoochie [10]

Answer:

F = 6.27 x 10 ¹⁹ N

Explanation:

Given

m₁ = 92 kg, m₂ = 46 kg, % = 0.04% N = 6.022 x 10²³ Z = 18, e = 1.6 x 10 ⁻¹⁹ C, M = 0.018 kg/mol

q₁ = % * [m * N * A * e / M ]

q₁ = 0.0004 * [ ( 92 kg * 6.022 x 10²³ * 18 * 1.6 x 10 ⁻¹⁹ ) / (0.018 kg/mol ) ]

q₁ = 3.54 x 10⁶ C

q₂ = 0.0004 * [ ( 46 kg * 6.022 x 10²³ * 18 * 1.6 x 10 ⁻¹⁹ ) / (0.018 kg/mol ) ]

q₂ = 1.773 x 10⁶ C

Now to determine the electrostatic force con use the equation

F = K * q₁ * q₂ / d²

K = 8.99 x 10 ⁹

F = 8.99 x 10 ⁹ * 3.54 x 10⁶ C * 1.773 x 10⁶ C / (30m)²

F = 6.27 x 10 ¹⁹ N

3 0

3 years ago

An ambulance emits a frequency of 450 Hz from its siren. What frequency is heard by a man as the ambulance moves toward him? les

Zepler [3.9K]

Frequency is defined as the number of repetitions of waves occurring in 1 second. The frequency heard by the man as the ambulance move toward him will be greater than 450 Hz.

<h3>What is the frequency ?</h3>

Frequency is defined as the number of cycles completed in 1 second. Frequency is given by the formula as,

$\rm{Frequency =\frac{1}{time } }$

As the formula shows frequency is inversely proportional to the time that shows if the time is decreasing frequency will increase and vice versa.

In the above case, the ambulance is moving toward the men. So that the time to meet up is decreased that's why the frequency will be greater than the initial frequency from the siren.

Hence the frequency heard by the man as the ambulance move toward him will be greater than 450 Hz.

To learn more about frequency refer to the link ;

brainly.com/question/4393505

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3 years ago

____________ occurs when an energy source transfers heat directly to another object through space; an example would be an object

lapo4ka [179]

B is the answer Radiation

5 0

3 years ago

Read 2 more answers

You want to see how your new belt buckle matches your new hat. Your eyes are 114 mm below the top of the hat and 800 mm above th

damaskus [11]

Answer:

$x=0.057m$

$h=0.457m$

Explanation:

From the question we are told that

Distance of eyes from the top of hat $d_1=114mm$

Distance of eyes from buckle $d_2=800mm$

Generally position of mirror relative eyes x is mathematically given as

$x=\frac{114}{2}$

$x=57mm$

$x=0.057m$

Generally the height of the mirror h is mathematically given as

$h=\frac{(Buckle\ below\ the\ hat)+(Buckle\ below\ the\ hat)}{2}$

$h=\frac{(114)+(800)}{2}$

$h=457mm$

$h=0.457m$

7 0

3 years ago

You are hiking along a trail in a wide, dry canyon where the outdoor temperature is T = 29.5° C. To determine how far you are aw

STALIN [3.7K]

Answer:

<em>The canyon is approximately 314 meters away</em>

Explanation:

<u>Speed of Sound</u>

If we emit sounds in an open space where a large obstacle (like a mountain) is expected to return the sounds, then it will travel forth and back at a given speed for a certain time. We can assume the speed of sound is constant, so we could know the approximate distance of the mountain (or canyon in our case) by the known formula.

$x=v_st$

Where $v_s$ is the speed of sound and t is half the time we hear our echo.

The speed of sound in m/s can be calculated from the approximate formula in terms of the temperature T in degrees Celsius

$v_s=331.3+0.606T$

We have $T=29.5^oC$ , so

$v_s=331.3+0.606(29.5)$

$v_s=349.177\ m/s$

Let's compute x, for t=1.8/2=0.9 seconds

$x=v_st=(349.177)(0.9)$

$x=314.26\ m$

The canyon is approximately 314 meters away

7 0

3 years ago