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3 years ago

Sound wave A has a lower frequency than sound wave B, but both waves

Physics

2 answers:

Keith_Richards [23]3 years ago

4 0

Answer: C

Explanation: Amplitude controls loudness, and frequency controls pitch. The more frequent the higher pitch.

tatuchka [14]3 years ago

3 0

Answer: C

explanation: its the only one that makes sense to me

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4. Two particles, A and B, are in uniform circular motion about a common center. The acceleration of particle A is 7.3 times tha

HACTEHA [7]

Answer:

Explanation:

Acceleration of particle A is 7.3 times the acceleration of particle B.

Let the acceleration of particle B is a, then the acceleration of particle A is

7.3 a.

Let the period of particle A is T and the period of particle B is 2.5 T.

Let the radius of particle A is RA and the radius of particle B is RB.

Use the formula for the centripetal force

$a=r\omega ^{2}=r\times \frac{4\pi^{2}}{T^{2}}$

So, $r = a\frac{T^{2}}{4\pi^{2}}$

The ratio of radius of A to the radius of B is given by

$\frac{R_{A}}{R_{B}}=\frac{a_{A}\times T_{A}^{2}}{a_{B}\times T_{B}^{2}}$

$\frac{R_{A}}{R_{B}}=\frac{7.3 a\times T^{2}}{a\times 6.25T^{2}}$

RA : RB = 1.17

3 0

3 years ago

Read 2 more answers

WILL MAKE BRAINLYEST!!!!!! PLZ HELP

mylen [45]

Answer:

Explanation:

4 0

4 years ago

What is the name of an ionic compound that consists of lithium ion LI and iodide ion (I)?

artcher [175]

Answer:

Lithium iodide

Explanation:

it's formula is LiI

Lithium iodide is a chemical compound composed of lithium and iodine, which when exposed to air turns yellow due to the oxidation of iodide to iodine. It has a chemical formula LiI.

The products, lithium iodide (LiI), sodium iodide (NaI), and cesium iodide (CsI) look like typical ionic compounds; they are all white crystalline solids

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2 years ago

2. (9 points) A car starts from 10 mph and accelerates along a level road, i.e., no grade change. At 500 ft from its starting po

Sonja [21]

Answer:

a) t = 11.2 s

b) v = 70.5 mph

Explanation:

Since we need to find the time, we could use the definition of acceleration (rearranging terms) as follows:

$t = \frac{v_{f} - v_{o}}{a} (1)$

where vf = 50 mph, and v₀ = 10 mph.
However, we still lack the value of a.
Assuming that the acceleration is constant, we can use the following kinematic equation:

$v_{f} ^{2} - v_{o} ^{2} = 2*a* \Delta x (2)$

Since we know that Δx = 500 ft, we could solve (2) for a.
In order to simplify things, let's first to convert v₀ and vf from mph to m/s, as follows:

$v_{o} = 10 mph*\frac{1609m}{1mi} *\frac{1h}{3600s} = 4.5 m/s (3)$

$v_{f} = 50 mph*\frac{1609m}{1mi} *\frac{1h}{3600s} = 22.5 m/s (4)$

We can do the same process with Δx, from ft to m, as follows:

$\Delta x = 500 ft *\frac{0.3048m}{1ft} = 152.4 m (5)$

Replacing (3), (4), and (5) in (2) and solving for a, we get:

$a = \frac{v_{f} ^{2} - v_{o}^{2}}{2*\Delta x} = \frac{(22.5m/s) ^{2} - (4.5m/s)^{2}}{2*152.4m} = 1.6 m/s2 (6)$

Replacing (6) in (1) we finally get the value of the time t:

$t = \frac{v_{f} - v_{o}}{a} = \frac{(22.5m/s) - (4.5m/s)}{1,6m/s2} = 11.2 s (7)$

Since the acceleration is constant, as we know the displacement is another 500 ft (152.4m), if we replace in (2) v₀ by the vf we got in a), we can find the new value of vf, as follows:

$v_{f} = \sqrt{v_{o} ^{2} +( 2*a* \Delta x)} = \sqrt{(22.5m/s)^{2} + (2*1.6m/s2*152.4m)} \\ v_{f} = 31.5 m/s (8)$