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3 years ago

PLEASE I NEED HELP ASAP!!!!!!!!!!

Physics

1 answer:

max2010maxim [7]3 years ago

3 0

tooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

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Two separate but nearby coils are mounted along the same axis. A power supply controls the flow of current in the first coil, an

Setler [38]

The ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.

<h3>Induced emf</h3>

An emf is induced in a coil placed in a magnetic field when a current carrying conductor moves in the field.

emf = NdФ/dt

where;

dФ is change in flux of the field
N is number of turns
dt is change in time

Thus, the ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.

Learn more about induced emf here: brainly.com/question/13744192

#SPJ1

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2 years ago

The dimension of Radius of gyration

serg [7]

Answer: So finally, the dimensional formula of the radius of gyration will be written as: [M0LT0]. The power of zero on the dimension of the mass and time shows that the mass and the time dimensions are zero for the radius of gyration. Hope this helps (:

4 0

3 years ago

A uniform, 4.5 kg, square, solid wooden gate 1.5 m on each side hangs vertically from a frictionless pivot at the center of its

Akimi4 [234]

Answer:

a) Angular speed(w) = 2.02rad/sec

b) 73J ( It is Inelastic Collision)

Explanation:

Given:

Mass=45kg

Length on each side = 1.5m side which is hangs vertically from a frictionless pivot at the center of its upper edge.

We need to calculate

(a) What is the angular speed and

(b) To know why the angular momentum conserved but not the linear momentum

CHECK THE ATTACHMENT FOR DETAILED EXPLATION

6 0

3 years ago

PLS HELPPPP WILL AWARD BRAINLIEST AND POINTS

Yuri [45]

Answer:

Here

Length (l) = 6 m

height (h) = 3 m

Load(L) = 500 N

Effort (E) = ?

we know the principal that

E * l = L * h

6 E = 500 * 3

6E = 1500

E = 250

therefore 250 N work is done on the barrel.

7 0

4 years ago

What is the energy difference between parallel and antiparallel alignment of the z component of an electron's spin magnetic dipo

Readme [11.4K]

Answer:

$\Delta U= 4.8204\times10^{-24} J$

Explanation:

The difference between parallel and anti parallel alignment of the z component of an electron's spin magnetic dipole moment is given by

$U_1-U_2= (-\mu Bcos(\theta_2))-(-\mu Bcos(\theta_1))$

where μ= dipole moment B= strength of magnetic field and θ= angle between direction of magnetic field and dipole

here θ_2 and θ_1 are 180 and 0° respectively.

$U_1-U_2= (\mu B)-(-\mu B)$

$U_1-U_2= 2\mu B$

here μ is bohr magnetron or magnetic moment of an electron = 9.27×10^{-24}

put this value we get

$U_1-U_2= 2\times 9.27\times10^{-24}(0.26)$

$\Delta U= 4.8204\times10^{-24} J$

3 0

3 years ago