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Vladimir [108]
3 years ago
14

We invest $3500 in an account that pays simple interest of 4% each year. How much interest is earned after 10 years?

Mathematics
1 answer:
krok68 [10]3 years ago
5 0

Answer:

$1400

Step-by-step explanation:

Take $3500 and multiply by 4% (0.4) and then get the product of 140 then multiply by 10 for the years and get $1400. Hope this answer helped!

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Step-by-step explanation:

6 0
3 years ago
2(x−23)=0 plz answer
Veronika [31]
Don’t get it what r the options
5 0
3 years ago
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Kazeer [188]
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7 0
2 years ago
Please help me
scZoUnD [109]
4x+y>-6
y>-4x-6
Then:
(-1,-1)
if x=-1; and y=-1

-1>-4(-1)-6
-1>4-6
-1>-2;    
(-1,-1) is a solution for this in-equation.

(0,-9)
0>-4(-9)-6
0>36-6
0>30    this is not true, therefore (0,-9) is not a solution.

(4,-20)
-20>-4(4)-6
-20>-16-6
-20>-22   This is true, therefore (4,-20) is a solution. 

(2,0)
0>-4(2)-6
0>-8-6
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(-3,6)
6>-4(-3)-6
6>12-6
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Answer: The next pairs are solutions to this inequality: (-1,-1) , (4,20), (2,0).

8 0
3 years ago
Austin is going to invest in an account paying an interest rate of 2.2% compounded daily. How much would Austin need to invest,
Korolek [52]

Answer:

  $23,700

Step-by-step explanation:

The compound interest formula can be helpful for this. Fill in the given values and solve for the unknown.

  FV = P(1 +r/n)^(nt)

where r is the annual interest rate, n is the number of times interest is compounded in a year, t is the number of years, P is the amount invested, and  FV is the future value of that investment.

  $27,000 = P(1 +0.022/365)^(365·6) = 1.1411037P

  P ≈ $23,700

5 0
3 years ago
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