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stellarik [79]
3 years ago
15

3. A woman drove her car from home to her daughter's school. The odometre on her dashboard says she travelled 4.5 km to do this.

She then immediately drove back home, using a different route, which was 5.5 km long. The whole journey took 30 minutes.
a. What distance did she travel?

b. What was her displacement?

C. What was her average speed during the journey?
Physics
1 answer:
11111nata11111 [884]3 years ago
5 0

Answer:

Look Below -->

Explanation:

a. She traveled 10 km, add 4.5 km + 5.5 km = 10 km (Distance is the total units travelled, so just add them all up :) )

b. Her displacement is  0 km because she went back home. (Displacement is the difference between the end and starting points)

c. 3 km/hr (30 minutes / 10 km)

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never [62]

Answer:

A) The wave that travels through the rail reaches the microphone first.

B) separation in time between the arrivals of the two pulses is 0.01539 seconds.

Explanation:

Detailed explanation and calculation is shown in the image below

4 0
3 years ago
When you push a child on a swing, your action is most effective when your pushes are timed to coincide with the natural frequenc
OleMash [197]

Answer:

T = 4.48 s

we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

Explanation:

Natural frequency of a simple pendulum of L length is given as

f = \frac{1}{2\pi}\sqrt{\frac{g}{L}}

so the time period of the oscillation is given as

T = 2\pi \sqrt{\frac{L}{g}}

so we will have

L = 5 m

T = 2\pi\sqrt{\frac{5}{9.81}}

T = 4.48 s

also from above formula we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

3 0
3 years ago
PLEASE HELP ME WITH THIS ONE QUESTION
Vlad [161]

Answer: 7.95^{\circ}C

Explanation:

Given

Mass of water is m_1=1\ kg

mass of ice is m_2=0.1\ kg

Latent heat of fusion L=3.33\times 10^5\ kJ/kg

The heat capacity of water is c_{w}=4186\ J/kg^{\circ}C

Suppose water is at  T^{\circ} C  and it reaches to 0^{\circ}C to melt the ice

the heat released by water must be equivalent to heat absorbed by the ice

\therefore \quad m_1c_w(T-0)=m_2\times L\\\Rightarrow 1\times 4186\times T=0.1\times 3.33\times 10^5\\\Rightarrow T=7.95^{\circ}C

6 0
3 years ago
At what angle should the axes of two polaroids be placed so as to reduce the intensity of the incident unpolarized light to 13.
prohojiy [21]

Answer:

θ = 66.90°

Explanation:

we know that

I= \frac{I_0}{2}cos^2\theta

I= intensity of polarized light =1

I_o= intensity of unpolarized light = 13

putting vales we get

1= \frac{13}{2}cos^2\theta

⇒\theta=cos^{-1} \sqrt{\frac{1}{6.5} }

therefore θ = 66.90°

5 0
3 years ago
A speedy tortoise can run with a speed of <img src="https://tex.z-dn.net/?f=v_T" id="TexFormula1" title="v_T" alt="v_T" align="a
Vinil7 [7]

Answer:

t_{H}  = t_{T}  - 60

Explanation:

Thinking process:

Let:

distance = speed × time

for the hare:

d_{H}  = s_{H} t_{H}

for the tortoise:

d_{T}  = s_{T} t_{T}

Let the length of the shell be s. Then the two are related. So:

d_{H}  = d_{T}  - s

Let's say the hare ran at x times the speed of the tortoise:

s_{H}  = xs_{T}

So, the equation still holds : t_{H}  = t_{T}  - 60

8 0
3 years ago
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