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Natali [406]
3 years ago
7

If you cut a piece of wood in half, each half would have *

Physics
1 answer:
Anon25 [30]3 years ago
7 0

Answer:

c

Explanation:

let's assume that you are splitting the piece of wood horizontally. This would not change the density of the wood at all, only the length. I rest my case. Ur awesome and have an amazing day.

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In science and physics what is the standard unit of measure for speed?
attashe74 [19]

meters per second or m/s

6 0
3 years ago
A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resist
7nadin3 [17]

Explanation:

The power P dissipated by a heater is defined as

P = VI

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

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b) The resistance <em>R</em><em> </em>of the heater is

P = VI = (IR)I = I^2R

where V= IR is our familiar Ohm's Law.

\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}

R = 110.8\:Ω

8 0
3 years ago
What volume of lead must be fastened underneath it to sink the wood in calm water so that its top is just even with the water le
astraxan [27]
The bouyancy force is:  

Since the wood-lead system is completely submerged, the bouyancy force 

 is FB = ĎwgVl + ĎwgVb, where Ďw is the density of water,Vl 

 is the volume of 

 the piece of lead and Vb is the volume of the wooden block. The weight of the

  combined lead and wooden block is: W = ĎlgVl + ĎbgVb. Since the system is 

 in equilibrium, the bouyancy force must be equal to the total weight: 

 ĎwgVl + ĎwgVb = ĎlgVl + ĎbgVb 

 now we can solve for the volume of lead: 

 ĎwgVl â’ ĎlgVl = ĎbgVb â’ ĎwgVb 

 Vl(Ďw â’ Ďl) = Vb(Ďb â’ Ďw) 

 Vl =   

 Ďbâ’Ďw 

 Ďwâ’Ďl   

 Vb 

 Now we substitute the values for the density of lead Ďl = 11.3 Ă— 103kg/m3  , 

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 . We get: 

 Vl =   

 600â’1000 

 1000â’11300 

 (0.6m Ă— 0.25m Ă— 0.08m) = 4.66 Ă— 10â’4m3
4 0
3 years ago
If θ=0rad
wlad13 [49]

Answer:

π

Explanation:

ok that is the answer ok

4 0
2 years ago
A force is applied to an object at rest with a mass of 100 kg. The same force is applied to an object at rest with a mass of 1 k
Darya [45]
The object with a mass of 100 kg would move slower than the object with a mass of 1 kg. This is because a greater force is required to move the object with a mass of 100 kg compared to the object of 1 kg.
3 0
3 years ago
Read 2 more answers
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