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3 years ago

What variables affect the acceleration of an object and in what manner do they affect the acceleration?

1 answer:

4 0

Acceleration, in physics, is the rate of change of velocity of an object. An object's acceleration is the net result of any and all forces acting on the object, as described by Newton's Second Law.

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What is the difference between VELOCITY and SPEED?

valentina_108 [34]

Answer:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector. ... In its simplest form, average velocity is calculated by dividing change in position (Δr) by change in time (Δt).

Explanation:

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4 years ago

What is the most important bone in your body plz help I will mark brainly

kompoz [17]

Answer:

<h2>Your skull protects the most important part of all, the brain. You can feel your skull by pushing on your head, especially in the back a few inches above your neck.</h2>

Explanation:

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3 years ago

Read 2 more answers

A gyroscope flywheel of radius 3.21 cm is accelerated from rest at 13.2 rad/s2 until its angular speed is 2450 rev/min.

SIZIF [17.4K]

Answer:

Part a)

$a_t = 0.423 m/s^2$

Part b)

$a_c = 2113 m/s^2$

Part c)

$d = 80 m$

Explanation:

Part a)

as we know that angular acceleration of the wheel is given as

$\alpha = 13.2 rad/s^2$

now the radius of the wheel is given as

R = 3.21 cm

so the tangential acceleration is given as

$a_t = R\alpha$

$a_t = (0.0321)(13.2)$

$a_t = 0.423 m/s^2$

Part b)

frequency of the wheel at maximum speed is given as

$f = 2450 rev/min$

$f = \frac{2450}{60} = 40.8 rev/s$

now we know that

$\omega = 2\pi f = 2\pi(40.8) = 256.56 rad/s$

now radial acceleration is given as

$a_c = \omega^2 r$

$a_c = (256.56)^2(0.0321) = 2113 m/s^2$

Part c)

total angular displacement of the point on rim is given as

$\Delta \theta = \omega_0 t + \frac{1}{2}\alpha t^2$

here we know that

$\omega = \omega_0 + \alpha t$

$256.56 = 0 + 13.2 t$

$t = 19.4 s$

now angular displacement will be

$\Delta \theta = 0 + \frac{1}{2}(13.2)(19.4)^2$

$\Delta \theta = 2493.3 rad$

now the distance moved by the point on the rim is given as

$d = R\theta$

$d = (0.0321)(2493.3)$

$d = 80 m$

7 0

3 years ago

Interrelationship between health population and environment education and Science and Technology

S_A_V [24]

Answer:

Answer: Science and technology are relatively modern developments. For most of the past 50,000 years of civilization, there was religion, dogma, ritual an tradition. These kept civilization safe but prevented growth.

After the modern scientific method was developed during the Rennaisance, civil action took off.

Health, as expressed as life expectancies, has increased massively. Population growth has increased to levels thought impossible before. But yes, the environment has suffered.

8 0

4 years ago

A piece of iron sinks to the bottom of a lake where the pressure is 21 times what it is at the surface of the lake. Which statem

san4es73 [151]

Answer:

A or B depending on your precision

Explanation:

In real life, applying to solid will shrink it depending on the amount of pressure applied, but due to the strength of solid bonds, the volume change is often negligible in practical situation and would only be accounted under astronomically high pressure phenomena (eg. at Jupiter's core or near black hole).

In high school level, and for many applications, it is entirely viable to completely neglect the change in solid volume under pressure. Thus, A is a legitimate answer. However, bear in mind that <em>in theory</em> the volume still decreases by a very slight amount. So B is correct as well, theoretically. The most correct option depends on the precision you needed.

5 0

3 years ago