Answer:
Acceleration and the distance traveled are 0.9 m/s² and 4.05 m
Explanation:
Given that,
Initail speed, u = 0
Final speed, v = 2.7 m/s
Time, t = 3 s
To find,
The acceleration and distance traveled.
Solution,
Acceleration is change in speed per unit time
Let s is the distance,
So, acceleration and the distance traveled are 0.9 m/s² and 4.05 m
Answer:
kg m/s
Explanation:
e = Charge = C
V = Voltage = 
c = Speed of light = m/s
Momentum is given by
The unit of MeV/c in SI fundamental units is kg m/s
That is a lunar eclipse. At night, when the Earth is between the Sun and the moon, the moon would appear to be red. Just for future reference, a solar eclipse is when the Moon is between the Sun and Earth. Speaking of which, check out the solar eclipse this August!
Answer:
0.5 rad / s
Explanation:
Moment of inertia of the disk I₁ = 1/2 MR²
M is mass of the disc and R is radius
Putting the values in the formula
Moment of inertia of the disc I₁ = 1/2 x 100 x 2 x 2
= 200 kgm²
Moment of inertia of man about the axis of rotation of disc
mass x( distance from axis )²
I₂ = 40 x 1.25²
= 62.5 kgm²
Let ω₁ and ω₂ be the angular speed of disc and man about the axis
ω₂ = tangential speed / radius of circular path
= 2 /1.25 rad / s
= 1.6 rad /s
ω₁ = ?
Applying conservation of angular moment ( no external torque is acting on the disc )
I₁ω₁ = I₂ω₂
200 X ω₁ = 62.5 X 1.6
ω₁ = 0.5 rad / s
Th equations to be used here are the following:
a = (v - v₀)/t
x = v₀t + 0.5at²
The speed of the fugitive is the sum of his own speed plus the speed of the train. Thus,
v₀ = 0 + 5.5 m/s = 5.5 m/s
v = 8 m/s + 5.5 m/s = 13.5 m/s
a.) We use the first equation to determine time
2.5 m/s² = (13.5 m/s - 5.5 m/s)t
Solving for t,
t = 3.2 seconds
b.) We use the answer in a) and the 2nd equation:
x = (5.5 m/s)(3.2 s) + 0.5(2.5 m/s²)(3.2 s)²
x = 30.4 meters
