Characteristics help scientists ________ objects.
2 answers:
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Answer:
a) 4.9 N/m
b) 1.4 m/s
c) 0.225 s
Explanation:
Hooke's law states that
F = k * Δx
Where
F: force applied to a spring
k: constant of the spring
Δx: elongation of the spring
The force applied in this case is the weight of the ball, this is
P = m * g = 0.1 kg * 9.81 m/s^2 = 0.981 N
Rearrainging Hooke's law:
k = F / Δx
k = 0.981 / 0.2 = 4.9 N/m
If the ball is pulled down the spring will acquire some potential energy, when it is released, the potential energy will be released as kinetic energy on the ball
Elastic potential energy is:
The energy gained from the 0.2m pull will be turned into kinetic energy
Ec = U
Therefore:
Rearranging:
After being released the ball will oscillate at the natural frequency of the system, which is
And the period will be:
The period in this case is:
The ball will move up and down taking T time to complete a cycle, the movement from the stretched position to the equilibrium position takes T/4 = 0.225 s
Answer:
Explanation:
As figure is not given so considering the most relevant diagram for question attached below
We can define Electric field as rate of change of electric potential with respect to space (say x-axis here). It is related in formula as
a) For Region A to B:
As can be seen from figure, point charge moves from 0 to 0.2 along x-axis, the value of electric potential remains constant i.e 5 volts
b) For Region B to C:
As point charge moves from B to C (0.2 to 0.4) along x-axis, the value of electric potential decreases from 5 volts to 3 volts. Electric field induced is:
c) For Region C to D:
As point charge moves from C to D (0.4 to 0.8) along x-axis, the value of electric potential decreases from 3 volts to 1 volt. Electric field induced is:
For Information:
Unit of Electric field is V/m or N/C
