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grandymaker [24]
4 years ago
5

a race car driver must average 203 km/h over the course of a time trial lasting ten laps. If the first nine laps were done at 19

9.0 km/h what average speed must be maintained for the last lap?
Physics
1 answer:
sashaice [31]4 years ago
4 0

Answer:

speed for last lap is 247.89 km/h

Explanation:

given data

velocity v1 = 203 km/h

velocity v2 = 199 km/h

no of lap n = 10

to find out

average speed for last lap

solution

we consider here distance d for 1 lap

so in first 9 lap time taken is

t1 = distance / velocity v2

t1 = 9d / 199    ...............1

and

for 10 lap time is

t2 = 10d / 203   .............2

so from 1 and 2 equation time for last lap

last lap time t3  = t2 - t1    

t3 = 10d / 203  -  9d / 199

t3 = 0.004034 d

so speed for last lap is

speed = distance / time

speed = d / 0.004034 d

speed = 247.89 km/h

so speed for last lap is 247.89 km/h

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Explanation:

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7 0
3 years ago
A daredevil is shot out of a cannon at 45.0° to the horizontal with an initial speed of 31.0 m/s. A net is positioned a horizont
hodyreva [135]

Answer:

s = vcos(x)t

50 = 25cos(45)t

cos(45)t = 2

t = 2/cos(45) = 2sqrt(2)

h = vsin(x)t + gt^2/2

h = 25sin(45)*2sqrt(2) - 4.9*8

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Explanation:

5 0
4 years ago
Read 2 more answers
The terms intrusive and extrusive are used to describe which one of the three rock groups
tino4ka555 [31]

Answer:

IGNEOUS ROCKS

Explanation: Igneous rocks are those rocks that solidify from magma.

Igneous rock is divided into two ,they are:

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8 0
3 years ago
Carbon dioxide in the blood is removed from the body through the A. kidneys B. lungs C. mouth D. skin​
natka813 [3]

Answer:

<h2>C) Mouth</h2>

Explanation:

<h2>When we inhale air, it contains oxygen. The lungs take in oxygen and the heart and the other body parts use it.</h2><h2>Carbon dioxide is removed from the blood mouth when we exhale.</h2>
8 0
3 years ago
A 0.40-kg block is attached to the end of a horizontal ideal spring and rests on a frictionless surface. The block is pulled so
lubasha [3.4K]

Answer:

160N/m

Explanation:

According to Hooke's law which states that the extension of an elastic material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically,

F = ke where

F is the applied force

k is the spring constant

e is the extension

From the formula k = F/e

Since the body accelerates when the block is released, F = ma according to Newton's second law of motion.

The spring constant k = ma/e where

m is the mass of the block = 0.4kg

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The spring constant of the spring is therefore 160N/m

4 0
3 years ago
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