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Ierofanga [76]
2 years ago
6

Rays of light coming from the sun (a very distant object) are near and parallel to the principal axis of a concave mirror. After

reflecting from the mirror, where will the rays cross each other at a single point?
The rays __________
a. will not cross each other after reflecting from a concave mirror.
b. will cross at the center of curvature.
c. will cross at the point where the principal axis intersects the mirror.
d. will cross at the focal point. will cross at a point beyond the center of curvature.
Physics
1 answer:
Setler [38]2 years ago
3 0

A concave mirror is an example of curved mirrors. So that the appropriate answer to the given question is option D. The rays will cross at the focal point.

A concave mirror is a type of mirror in which its inner part is the reflecting surface, while its outer part is the back of the mirror.  This mirror reflects all parallel rays close to the principal axis to a point of convergence. It can also be referred to as the converging mirror.

In this type of mirror, all rays of light parallel to the principal axis of the mirror after reflection will cross at the focal point.

Therefore, the required answer to the given question is option D. i.e The rays will cross at the focal point.

For reference: brainly.com/question/20380620

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Using the given equation you get:

E = 1.99x10^-25 / 9.0x10^-6

Divide 1.99 by 9.0: 1.99/9.0 = 0.22

For the scientific notation, when dividing subtract the two exponents:

25 -6 = 19

So you now have 0.22 x 10^-19

Now you need to change the 0.22 to be in scientific notation form:

2.2 x 10^-20

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Answer:

\frac{F}{W} = 9.37 \times 10^{-4}

Explanation:

Radius of the pollen is given as

r = 12.0 \mu m

Volume of the pollen is given as

V = \frac{4}{3}\pi r^3

V = \frac{4}{3}\pi (12\mu m)^3

V = 7.24 \times 10^{-15} m^3

mass of the pollen is given as

m = \rho V

m = 7.24 \times 10^{-12}

so weight of the pollen is given as

W = mg

W = (7.24 \times 10^{-12})(9.81)

W = 7.1 \times 10^{-11}

Now electric force on the pollen is given

F = qE

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F = 6.65 \times 10^{-14} N

now ratio of electric force and weight is given as

\frac{F}{W} = \frac{6.65 \times 10^{-14}}{7.1 \times 10^{-11}}

\frac{F}{W} = 9.37 \times 10^{-4}

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