It would be d all of the above
Explanation:
The electric field at a distance r from the charged particle is given by :

k is electrostatic constant
if r = 2 m, electric field is given by :

If r = 1 m, electric field is given by :

Dividing equation (1) and (2) we get :

So, at a point 1 m from the particle, the electric field is 4 times of the electric field at a point 2 m.
Answer:
Sagittarius A
Explanation:
The center of the milky way has a big giant hole known as "Sagittarius A". The size is 4 million times bigger than the sun.