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Harman [31]
3 years ago
10

Plz help... asap I need it

Physics
2 answers:
ehidna [41]3 years ago
7 0
8000 j is the answer
riadik2000 [5.3K]3 years ago
3 0
8000 J is the answer
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Calculate the speed of an object having momentum 7.25 x 10^5 kg.m/s and mass 0.285 kg. Answer in units of m/s.
Olenka [21]

Answer:

speed is 25.43 85 x 10^5  m/s

Explanation:

momentum = 7.25 x 10^5 kg.m/s

mass = 0.285 kg

to find out

speed

solution

we have given mass and momentum so

to find speed we apply here momentum formula that is

momentum = mass × speed   ...................1

put here all value and find speed

speed = momentum / mass

speed = 7.25 x 10^5 / 0.285

speed = 2543859.649

so speed is 25.43 85 x 10^5  m/s

3 0
3 years ago
In which of the following situations do the particles of the medium oscillate only parallel to the motion of the wave?
uysha [10]
Hi!

I believe the answer is A . energy transmitted by the cry of an eagle.
The particles of the medium oscillate only parallel to the motion of the wave transmitted by the cry of an eagle .

Hope it helps and have a wonderful day !
6 0
3 years ago
Read 2 more answers
is it possible for the gravitational force between two 50-kg objects to be less than the gravitational force between a 59-kg obj
Eva8 [605]

OF COURSE !  

The gravitational force between two objects doesn't ONLY depend on the product of their masses.  It also depends on the distance between them.

I'm not even going to work out the numbers for my example.  I'm just going to state without proof that at the top of the 2nd frame, the gravitational force between you and your bowling ball is greater than the gravitational force between you and the whole darn Andromeda galaxy !  My reasoning is based on the fact that your bowling ball is maybe 1 foot from your center of mass, whereas the Andromeda galaxy is more like 2.5 million light years from it.  That right there is going to give your bowling ball a big advantage when it comes to gravity !

5 0
3 years ago
1. Calculate how many electrons you need to get a charge of 1 coulomb.
belka [17]

1) To make a charge of 1 Coulomb, 6.25\cdot 10^{18} electrons are needed

2) 3.75\cdot 10^{19} electrons are needed to make that current

3) The potential difference is the work done per unit charge by an electric field

4) False, false, true

Explanation:

1)

The charge of one electron is equal to (in magnitude)

q=1.6\cdot 10^{-19}C

This is also known as fundamental charge, and it is also indicated with the letter e.

The charge in this problem is

Q=1 C

Therefore, in order to calculate how many electrons are in 1 Coulombd of charge, we just divide the total charge by the charge of one electron:

n=\frac{Q}{q}=\frac{1}{1.6\cdot 10^{-19}}=6.25\cdot 10^{18}

2)

The current intensity is defined as

I=\frac{Q}{t}

where

Q is the charge passing through a given point of a circuit in a time interval t

In this problem, we have

t = 60 s

I = 100 mA = 0.1 A

Therefore, the charge passing through the circuit is

Q=It=(0.1)(60)=6 C

We know that the charge of one electron is

q=1.6\cdot 10^{-19}C

So the number of electrons is

n=\frac{Q}{q}=\frac{6}{1.6\cdot 10^{-19}}=3.75\cdot 10^{19}

3)

The electrical voltage (also called potential difference) can be understood by using the concept of energy and work.

In fact, the work done by an electric field on a charge of magnitude q is

W=q\Delta V (1)

where \Delta V is the potential difference between the initial and final point of motion of the charge. The potential difference is responsible for "pushing" the charge through the circuit (in particular, a positive charge is pushed towards a point of lower potential, while a negative charge is pushed towards a point of higher potential), and when this happens, the electric potential energy of the charge (due to its position in the electric field) is converted into kinetic energy (energy of motion).

So, the potential difference is basically the work done per unit charge by an electric field responsible for the acceleration of a charge, as we can rewrite eq.(1) as

\Delta V = \frac{W}{q}

So in this case (where the electric voltage is 5 volts), it means that the work done by this electric field per unit charge is 5 J per Coulomb of charge.

4)

False: Current is the consequence and voltage is the cause. In fact, the voltage (the potential difference between two points in the circuit) is responsible for "pushing" the charges through the circuit, and when the charges start moving, they produce a current.

False: only the battery is a source of voltage. A battery is a device that produces an electromotive force (another name for potential difference), which is responsible for "pushing" the charges through the circuit. A socket, instead, is just a device used to connect another electric device to a voltage supply.

True: an electric current can only flow in a closed circuit. When the circuit is open, in fact, there is a point in the circuit where the flow of charge is interrupted: this means that the current can no longer flow in the circuit, so there is no electric current in an open circuit.

Learn more about current and potential difference:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

4 0
4 years ago
In midair an M = 145 kg bomb explodes into two pieces of m1 = 115 kg and another, respectively. Before the explosion, the bomb w
Daniel [21]

Answer:

v_2=-133.17m/s, the minus meaning west.

Explanation:

We know that linear momentum must be conserved, so it will be the same before (p_i) and after (p_f) the explosion. We will take the east direction as positive.

Before the explosion we have p_i=m_iv_i=Mv_i.

After the explosion we have pieces 1 and 2, so p_f=m_1v_1+m_2v_2.

These equations must be vectorial but since we look at the instants before and after the explosions and the bomb fragments in only 2 pieces the problem can be simplified in one dimension with direction east-west.

Since we know momentum must be conserved we have:

Mv_i=m_1v_1+m_2v_2

Which means (since we want v_2 and M=m_1+m_2):

v_2=\frac{Mv_i-m_1v_1}{m_2}=\frac{Mv_i-m_1v_1}{M-m_1}

So for our values we have:

v_2=\frac{(145kg)(24m/s)-(115kg)(65m/s)}{(145kg-115kg)}=-133.17m/s

5 0
3 years ago
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