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Ugo [173]
3 years ago
13

A 0.650 kg block is attached to a spring with spring constant 18.0 N/m . While the block is sitting at rest, a student hits it w

ith a hammer and almost instantaneously gives it a speed of 47.0 cm/s . What are
The amplitude of the subsequent oscillations? answer is in cm

The block's speed at the point where x= 0.350 A? answer is in cm/s
Physics
1 answer:
garik1379 [7]3 years ago
3 0

Answer:

amplitude is 8.92 cm

speed of block is 44.11 cm/s

Explanation:

given data

mass = 0.650 kg

spring constant = 18 N/m

speed = 47 cm/s = 0.44 m/s

speed at x point = 0.350 A

to find out

amplitude of subsequent oscillation

solution

we know here conservation of energy

maximum kinetic energy = maximum potential energy

\frac{1}{2} m v^{2} = \frac{1}{2} k A^{2}

here we know k is spring constant and m is mass and A is amplitude and v is velocity

so solve it we get

A = \sqrt{\frac{mv^{2} }{k} }

put here all these value

A =  \sqrt{\frac{0.650(0.47)^{2} }{18} }

A = 0.08931 m

so amplitude is 8.92 cm

and

by conservation of energy

initial energy = final energy

\frac{1}{2} m V^{2} + \frac{1}{2} k x^{2} = \frac{1}{2} m Vm^{2} + 0

solve we gey V

V = \sqrt{Vm^{2} - \frac{k }{m} x^{2} }    

put here value Vm = 0.47 , and x = 0.350

V = \sqrt{0.47^{2} - \frac{18 }{0.650} (0.350*0.088 m)^{2} }

V = 0.4411 m/s

so speed of block is 44.11 cm/s

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This natural resistance is known as inertia. =)
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3 years ago
1) An average soccer ball has a mass of .4 kg. If a soccer ball is kicked with a force of 750 Newtons, what is the acceleration
Y_Kistochka [10]

Answer:

Explanation:

#1 uses Newton's 2nd Law: F = ma so filling in:

750 = .4a and

a = 1875 m/s/s

#2 uses d = rt so

d = 12.3(25) and

d = 307.5 m

5 0
3 years ago
Find the electric field at a point midway between two charges of +40.0 x 10^-9 c and.+60.0 x 10^-9 c
PIT_PIT [208]
Missing part in the text: "...the charges are <span>separated by a distance of 30.0 cm."
</span>
Solution:
The point midway between the two charges is located 15.0 cm from one charge and 15.0 from the other charge. The electric field generated by each of the charges is
E=k_e \frac{q}{r^2}
where
ke is the Coulomb's constant
Q is the value of the charge
r is the distance of the point at which we calculate the field from the charge (so, in this problem, r=15.0 cm=0.15 m).

Let's calculate the electric field generated by the first charge:
E_1 = (8.99 \cdot 10^9 Nm^2 C^{-2} ) \frac{+40.0 \cdot 10^{-9} C}{(0.15 m)^2}=1.6 \cdot 10^4 N/C

While the electric field generated by the second charge is
E_2 = (8.99 \cdot 10^9 N m^2 C^{-2} ) \frac{+60.0 \cdot 10^{-9} C}{(0.15 m)^2}=2.4 \cdot 10^4 N/C

Both charges are positive, this means that both electric fields are directed toward the charge. Therefore, at the point midway between the two charges the two electric fields have opposite direction, so the total electric field at that point is given by the difference between the two fields:
E=E_2 - E_1 = 2.4 \cdot 10^4 N/C - 1.6 \cdot 10^4 N/C = 8000 N/C
4 0
3 years ago
What property describes the ability of a material to be flattened into thin sheets by hammering? options:
Ivanshal [37]
D. malleability is the ability to bend or form something ? like if something is malleable you can bend it
8 0
3 years ago
Read 2 more answers
Which one of the following phrases best describes the electric potential of a charged particle?
vfiekz [6]

Answer:

D.The potential energy per unit charge

Explanation:

Electric potential of a charged particle:

It is scalar quantity because it has magnitude but it does not have direction.

It is the amount of work done required to move a unit positive charge from reference point to specific point in the electric field without producing any acceleration.

Mathematical representation:

V=\frac{W}{Q_0}

Where W= Work done

Q_0= Unit positive charge

Other formula to calculate electric field:

V=\frac{KQ}{r}

Where K=\frac{1}{4\pi \epsilon_0}

It can be defined as potential energy per unit charge.

Hence, option D is true.

4 0
4 years ago
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