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3 years ago

What is the vertical acceleration of a paper airplane that is launched horizontally with an initial velocity of 2.3 m/s?

Physics

1 answer:

mr_godi [17]3 years ago

8 0

Answer:

The vertical acceleration is -9.81 m/s^2

Explanation:

When a body is projected, the body experiences an acceleration in the vertical axis that is proportional to the acceleration due to gravity of the earth, which is equal to 9.81 m/s^2. In this case, the acceleration acts to stop the vertical motion of the paper plane, and hence is a deceleration, which explains the negative vertical acceleration.

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HELP ASAP!! WILL MARK BRAINLIEST!! WRITE IN YOUR OWN WORDS!! What is something that you would like to see a physicist develop in

Schach [20]

Answer:

Phones as sunglasses with a mic. I put on my glasses and I say what's the weather today, The sunglasses will tell me the weather and can be charged just like phones

Explanation:

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3 years ago

Which feature of an object affects its weight? Select three options.

Vadim26 [7]

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3 years ago

A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors

Mars2501 [29]

Answer:

(A) Capacitance per unit length = $4.02 \times 10^{-10}$

(B) The magnitude of charge on both conductor is $Q = 4.22 \times 10^{-19}$ C and the sign of charge on inner conductor is $+Q$ and the sign on outer conductor is $-Q$

Explanation:

Given :

Radius of inner part of conductor $(R_{1})$ = $2.7 \times 10^{-3}$ m

Radius of outer part of conductor $(R_{2})$ = $3.1 \times 10^{-3}$ m

The length of the capacitor $(l)$ = $3 \times 10^{-3}$ m

(A)

Capacitance is purely geometrical property. It depends only on length, radius of conductor.

From the formula of cylindrical capacitor,

$C = \frac{2\pi\epsilon_{o} l }{ln\frac{R_{2} }{R_{1} } }$

Where, $\epsilon_{o} = 8.85 \times 10^{-12}$

But we need capacitance per unit length so,

$\frac{C}{l} = \frac{2\pi\epsilon_{o} }{ln\frac{R_{2} }{R_{1} } }$

capacitance per unit length = $\frac{6.28 \times 8.85 \times 10^{-12} }{ln(1.148)} = 4.02 \times 10^{-10}$

(B)

The charge on both conductors is given by,

$Q = C \Delta V$

Where, C = capacitance of cylindrical capacitor and value of $C = 12.06 \times 10^{-13}$ F, $\Delta V = 350 \times 10^{-3}$ V

∴ $Q = 4.22 \times 10^{-19}$ C

The magnitude of charge on both conductor is same as above but the sign of charge is different.

Charge on inner conductor is $+Q$ and Charge on outer conductor is $-Q$ .

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3 years ago

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grin007 [14]

<h3>Answer;</h3>

The spheres develop opposite charges. 
Electrons move from Sphere A to Sphere B. 
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<h3>Explanation;</h3>

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Thus, the sphere will develop opposite charges, electrons will move from Sphere A to sphere B, hence we say that the spheres will be charged by induction such that sphere A will acquire a positive charge while sphere B will acquire negative charge.

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Inessa [10]

Answer:

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