Answer:
Explanation:
The energy delivered to the resistive coil is dissipated as heat at a rate equal to the power input of the circuit. However, not
all of the energy in the circuit is dissipated by the coil. Because the emf source has internal resistance, energy is also dissipated by the battery as heat. Calculate the rate of dissipation of energy PbatPbatP_bat in the battery.
1 answer:
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Answer:
Radius of the circle will be 2.5 m
Explanation:
We have given velocity of particle moving in the circle v = 5 m/sec
Acceleration of particle in the circle
We have to find the radius of the circle
We know that acceleration is given by
So
So radius of the circle will be 2.5 m