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miss Akunina [59]
3 years ago
10

The energy delivered to the resistive coil is dissipated as heat at a rate equal to the power input of the circuit. However, not

all of the energy in the circuit is dissipated by the coil. Because the emf source has internal resistance, energy is also dissipated by the battery as heat. Calculate the rate of dissipation of energy PbatPbatP_bat in the battery.

Physics
1 answer:
Nata [24]3 years ago
4 0

Answer:

P = I²r

Explanation:

ε= IR + Ir

where r is the internal resistance

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<em></em>

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