The energy delivered to the resistive coil is dissipated as heat at a rate equal to the power input of the circuit. However, not
all of the energy in the circuit is dissipated by the coil. Because the emf source has internal resistance, energy is also dissipated by the battery as heat. Calculate the rate of dissipation of energy PbatPbatP_bat in the battery.
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If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C
<u>Given the following the details;</u>
- Energy = 40 Joules
- Electric potential = 8 Volts
To find the quantity of charge;
Mathematically, the quantity of charge with respect to electric potential is given by the formula;
Substituting the values into the formula, we have;
<em>Quantity of charge = 5 Coulombs</em>
Therefore, the quantity of charge must be <em>5 Coulombs.</em>
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