There is need 4.5 hours to fill the pool in case if both pipes are open
Answer:
= 3.869 × 10^-6 J/m³
Explanation:
Intensity is given as W/m^2 which is equivalent to J/ (s*m^2)
Speed of light is 2.99792 × 10^8 m/s.
Therefore;
Electromagnetic energy per cubic meter = Intensity/speed of light
= 1160 J/ (s*m³)/ 2.99792 × 10^8 m/s.
<u>= 3.869 × 10^-6 J/m³</u>
Answer:
(a) 1.054 m/s²
(b) 1.404 m/s²
Explanation:
0.5·m·g·cos(θ) - μs·m·g·(1 - sin(θ)) - μk·m·g·(1 - sin(θ)) = m·a
Which gives;
0.5·g·cos(θ) - μ·g·(1 - sin(θ) = a
Where:
m = Mass of the of the block
μ = Coefficient of friction
g = Acceleration due to gravity = 9.81 m/s²
a = Acceleration of the block
θ = Angle of elevation of the block = 20°
Therefore;
0.5×9.81·cos(20°) - μs×9.81×(1 - sin(20°) - μk×9.81×(1 - sin(20°) = a
(a) When the static friction μs = 0.610 and the dynamic friction μk = 0.500, we have;
0.5×9.81·cos(20°) - 0.610×9.81×(1 - sin(20°) - 0.500×9.81×(1 - sin(20°) = 1.054 m/s²
(b) When the static friction μs = 0.400 and the dynamic friction μk = 0.300, we have;
0.5×9.81·cos(20°) - 0.400×9.81×(1 - sin(20°) - 0.300×9.81×(1 - sin(20°) = 1.404 m/s².
Answer:The speed is 54 mm/s, the units are mm/s.
Explanation:
1) Data:
a) λ = 6mm
b) f = 9 Hz = 9 s⁻¹
c) v = ?
2) Formula:
wave equation: v = f × λ
3) Solution:
v = 9 s⁻¹ × 6mm
v = 54 mm/s
The speed is 54 mm/s, the units are mm/s.
