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frutty [35]
3 years ago
6

Force is a vector due to its mass being a vector quantity: O True O False

Physics
1 answer:
Whitepunk [10]3 years ago
6 0

Answer:

False

Explanation:

It is a vector because of the acceleration being a vector. F=ma.

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A car goes from rest to a speed of 90 km/h in 10 seconds . What is the car's acceleration in m/s²
zloy xaker [14]
First you must convert Km/hr to m/s. 90 km/hr equals 25m/s (this can be done through a conversion table by plugging in the conversion values). Then you need to see what was given:
vi (initial velocity)= 0m/s
vf (final velocity= 25m/s (90km/hr)
t (time)= 10s

Next you should find an equation that requires only the values you know and gives you the value you're looking for. Sometimes that requires two equations to be used, but in this case you only need one. The best equation for this would be a=(vf-vi)/t. Finally, plug in your values (a=(25-0)/10) to get your answer which would be 2.5m/s^2. Hope this helped!
7 0
3 years ago
Select the correct answer.
BaLLatris [955]

It is due to the excess stress.

6 0
3 years ago
A waiter carries a plate on top of his arm. The waiter's arm applies an upward force to the plate and holds it up. This force is
Phantasy [73]
I believe it is away from his arm since the question states his arm is applying an upwards force
6 0
3 years ago
Read 2 more answers
Suppose a door is 1 meter wide. Calculate the difference in the amount torque exerted on the door when someone pushes with a con
Yanka [14]

Answer:

Δτ = 50 N.m

Explanation:

The torque applied on an object is given by the product of the force applied on it and the perpendicular distance between the force and the axis of rotation of the object. That is:

τ = F r

where,

τ = Torque applied on the object

F = Force applied on it

r = distance from axis of rotation

<u>FOR HANDLE SIDE OF DOOR</u>:

τ₁ = F r₁

where,

τ₁ = Torque applied on the object = ?

F = Force applied on it = 100 N

r₁ = distance from axis of rotation = 1 m

Therefore,

τ₁ = (100 N)(1 m)

τ₁ = 100 N.m

<u></u>

<u>FOR MIDDLE OF DOOR</u>:

τ₂ = F r₂

where,

τ₂ = Torque applied on the object = ?

F = Force applied on it = 100 N

r₂ = distance from axis of rotation = 1 m/2 = 0.5 m

Therefore,

τ₂ = (100 N)(0.5 m)

τ₂ = 50 N.m

Now, the difference between the amount of torque in both cases is:

Δτ = τ₁ - τ₂

Δτ = 100 N.m - 50 N.m

<u>Δτ = 50 N.m</u>

6 0
3 years ago
A typical atomic polarizability is 1 × 10-40 (C·m)/(N/C). If the q in p = qs is equal to the proton charge e, what charge separa
Alenkasestr [34]

Answer:

s = 6.25 10⁻²² m

Explanation:

Polarizability is the separation of electric charges in a structure, in the case of the atom it is the result of the separation of positive charges in the nucleus and the electrons in their orbits, macroscopically it is approximated by

                p = q s

               s = p / q

let's calculate

              s = 1 10⁻⁴⁰ / 1.6 10⁻¹⁹

              s = 0.625 10⁻²¹ m

              s = 6.25 10⁻²² m

We see that the result is much smaller than the size of the atom, therefore this simplistic model cannot be taken to an atomic scale.

6 0
3 years ago
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