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3 years ago

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BaLLatris [955]3 years ago

6 0

It is due to the excess stress.

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Which force causes all objects with mass to attract one another?

Scrat [10]

Gravitational force

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3 years ago

Ranboo <br><br> ⏚⟒⟒⌿<br><br> :) <3 have a good day

bearhunter [10]

Ranboo oobnar have a good day

4 0

3 years ago

Read 2 more answers

10. A book has a mass of 400 g. The surface of the book in contact with a table has dimensions 0.10m x 0.20 m. The gravitational

morpeh [17]

The pressure exerted on the table due to the book is 200 N/m².

The given parameters;

<em>mass of the book, m = 400 g = 0.4 kg</em>
<em>dimension of the table, = 0.10m x 0.20 m.</em>
<em>gravitational field strength g = 10 N/kg.</em>

The area of the table is calculated as follows;

A = 0.1 x 0.2 = 0.02 m²

The pressure exerted on the table due to the book is calculated as follows;

$P = \frac{F}{A}$

where;

<em>F is the force of the book due to its weight</em>

<em />

$P =\frac{F}{A} = \frac{mg}{A} = \frac{0.4 \times 10}{0.02} = 200 \ N/m^2$

Thus, the pressure exerted on the table due to the book is 200 N/m².

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8 0

2 years ago

Meteor Infrasound A meteor that explodes in the atmosphere creates infrasound waves that can travel multiple times around the gl

ladessa [460]

Answer:

The frequency of these waves is $4.27\times10^{-2}\ Hz$

Explanation:

Given that,

Wavelength = 6.6 km

Distance = 8810 km

Time t = 8.67 hr

We need to calculate the velocity of sound

Using formula of velocity

$v = \dfrac{D}{T}$

Where, D = distance

T = time

Put the value into the formula

$v =\dfrac{8810}{8.67}$

$v=1016\ km/hr$

We need to calculate the frequency

Using formula of frequency

$v=n\lambda$

$n=\dfrac{v}{\lambda}$

Put the value into the formula

$n=\dfrac{1016}{6.6}$

$n=153.93\ hr$

$n=\dfrac{153.93}{60\times60}$

$n=0.0427\ Hz$

$n=4.27\times10^{-2}\ Hz$

Hence, The frequency of these waves is $4.27\times10^{-2}\ Hz$

8 0

3 years ago

You lift a 25-kg child 0.80 m, slowly carry him 10 m to the playroom, and finally set him back down 0.80 m onto the playroom flo

maksim [4K]

To solve this problem we will apply the work theorem which is expressed as the force applied to displace a body. Considering that body strength is equivalent to weight, we will make the following considerations

$\text{Mass of the child} = m = 25kg$

$\text{Acceleration due to gravity} = g = 9.81m/s^2$

$\text{Height lifted} = h = 0.80m (Upward)$

Work done to upward the object

$W = mgh$

$W = (25)(9.81)(0.8)$

$W = 196.2J$

Horizontal Force applied while carrying 10m,

$F = 0N$

$W = 0J$

Height descended in setting the child down

$h' = -0.8m (Downwoard)$

$W = mgh'$

$W = (25)(9.81)(-0.80)$

$W = -196.2J$

For full time, assuming that the total value of work is always expressed in terms of its symbol, it would be zero, since at first it performs the same work that is later complemented in a negative way.

6 0

3 years ago