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3 years ago

Select the correct answer.

Physics

1 answer:

BaLLatris [955]3 years ago

6 0

It is due to the excess stress.

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How far apart are two conducting plates that have an electric field strength of 8.53 x 103 V/m between them, if their potential

sleet_krkn [62]

Answer:

$d=2.7m$

Explanation:

From the question we are told that:

Electric Field strength $E=8.53 * 10^3 V/m$

Potential difference is $V= 23.0 kV$

Generally the equation for distance is mathematically given by

$d=\frac{V}{E}$

$d=\frac{23.0*10^3}{8.53 * 10^3 V/m}$

$d=2.7m$

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3 years ago

If you dropped a ball off a building, how far would it fall in 3 seconds?

tangare [24]

If you drop a ball off a building it increases its speed by 10 m/s so in 3 seconds it’s speed would be 30 m/s and it’s distance would be 45m

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4 years ago

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shutvik [7]

Answer:

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3 years ago

715 J of heat are transferred from

bezimeni [28]

Answer:1.99

Explanation:

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3 years ago

A 1000-kg car traveling north at 15 m/s collides with a2000-kg truck traveling east at 10 m/s. The occupants, wearing seat belts

Aleksandr-060686 [28]

Answer:

8.33 m/s, 36.87° North of East

Explanation:

$m_n$ = Mass of car = 1000 kg

$v_n$ = Velocity of car = 15 m/s

$m_e$ = Mass of truck = 2000 kg

$v_e$ = Velocity of truck = 10 m/s

M = Combined mass = 1000+2000 = 3000 kg

Momentum

$p_n=m_nv_n\\\Rightarrow p_n=1000\times 15\\\Rightarrow p_n=15000\ kgm/s$

Momentum of car traveling East is 15000 kgm/s

$p_e=m_ev_e\\\Rightarrow p_n=2000\times 10\\\Rightarrow p_n=20000\ kgm/s$

Momentum of truck traveling North is 20000 kgm/s

Angle

$\theta=tan^{-1}\frac{p_n}{p_e}\\\Rightarrow \theta=tan^{-1}\frac{15000}{20000}\\\Rightarrow \theta=36.87^{\circ}$

As the two vehicles are vectors, the resultant velocity is

$(Mv)^2=p_n^2+p_e^2\\\Rightarrow v=\sqrt{\frac{p_n^2+p_e^2}{M^2}}\\\Rightarrow v=\sqrt{\frac{15000^2+20000^2}{3000^2}}\\\Rightarrow v=8.33\ m/s$

Velocity of the two vehicles when they are locked together is 8.33 m/s and direction is 36.87° North of East

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3 years ago